在java List中进行模糊查询的实现方法

比如我有下面这样一个List，里面存放的是多个Employee对象。然后我想对这个List进行按照Employee对象的名字进行模糊查询。有什么好的解决方案么？

比如我输入的查询条件为“wang”，那么应该返回只包含employee1的List列表。

List list = new ArrayList();
Employee employee1 = new Employee();
employee1.setName("wangqiang");
employee1.setAge(30);
list.add(employee1);
Employee employee2 = new Employee();
employee2.setName("lisi");
list.add(employee2);
employee2.setAge(25);

 方式一：

public List search(String name,List list){
  List results = new ArrayList();
  Pattern pattern = Pattern.compile(name);
  for(int i=0; i < list.size(); i++){
   Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
   if(matcher.matches()){
     results.add(list.get(i));
   }
  }
  return results;
}

上面那个是大小写敏感的，如果要求大小写不敏感，改成：

Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);

并且上面那个是精确查询，如果要模糊匹配，matcher.find()即可以进行模糊匹配

public List search(String name,List list){
  List results = new ArrayList();
  Pattern pattern = Pattern.compile(name);
  for(int i=0; i < list.size(); i++){
   Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
   if(matcher.find()){
     results.add(list.get(i));
   }
  }
  return results;
}

方式二：

public class ListLike {

//定义员工类
public class Employee {
private String name;
private int age;
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}

public List list=new ArrayList();

//增加员工
public List addList(String name,int age){
Employee employee1 = new Employee();
employee1.setName(name);
employee1.setAge(age);
list.add(employee1);
return list;
}

//显示所有员工
public void ShowList(){
for(int i=0;i<list.size();i++){
System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge());
}
}

//模糊查询
public List likeString(String likename){
for(int i=0;i<list.size();i++){
if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1)
list.remove(i);
}
return list;

}

public static void main(String arg[]){
ListLike ll=new ListLike();
ll.addList("wuxiao",13);
ll.addList("wangwang",11);
ll.addList("wanghua",12);
ll.addList("xiaowang",13);
ll.addList("xiaoxiao",13);

ll.likeString("wang");
ll.ShowList();

}

}

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