C++实现LeetCode(121.买卖股票的最佳时间)

[LeetCode] 121.Best Time to Buy and Sell Stock 买卖股票的最佳时间

Say you have an array for which the ith element is the price of a given stock on day i.

If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit.

这道题相当简单，感觉达不到Medium的难度，只需要遍历一次数组，用一个变量记录遍历过数中的最小值，然后每次计算当前值和这个最小值之间的差值最为利润，然后每次选较大的利润来更新。当遍历完成后当前利润即为所求，代码如下：

C++ 解法：

class Solution {
public:
    int maxProfit(vector<int>& prices) {
        int res = 0, buy = INT_MAX;
        for (int price : prices) {
            buy = min(buy, price);
            res = max(res, price - buy);
        }
        return res;
    }
};

Java 解法：

public class Solution {
    public int maxProfit(int[] prices) {
        int res = 0, buy = Integer.MAX_VALUE;
        for (int price : prices) {
            buy = Math.min(buy, price);
            res = Math.max(res, price - buy);
        }
        return res;
    }
}

类似题目：

Best Time to Buy and Sell Stock with Cooldown

Best Time to Buy and Sell Stock IV

Best Time to Buy and Sell Stock III

Best Time to Buy and Sell Stock II

到此这篇关于C++实现LeetCode(121.买卖股票的最佳时间)的文章就介绍到这了,更多相关C++实现买卖股票的最佳时间内容请搜索我们以前的文章或继续浏览下面的相关文章希望大家以后多多支持我们！

赞 (0)

相关推荐

  • C++实现LeetCode(114.将二叉树展开成链表)

    [LeetCode] 114. Flatten Binary Tree to Linked List 将二叉树展开成链表 Given a binary tree, flatten it to a linked list in-place. For example, Given 1 / \ 2   5 / \   \ 3   4   6 The flattened tree should look like:    1 \ 2 \ 3 \ 4 \ 5 \ 6 click to show hints

  • C++实现LeetCode(142.单链表中的环之二)

    C++实现LeetCode(142.单链表中的环之二)

    [LeetCode] 142. Linked List Cycle II 单链表中的环之二 Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexe

  • C++实现LeetCode(116.每个节点的右向指针)

    C++实现LeetCode(116.每个节点的右向指针)

    [LeetCode] 116. Populating Next Right Pointers in Each Node 每个节点的右向指针 You are given a perfect binary tree where all leaves are on the same level, and every parent has two children. The binary tree has the following definition: struct Node { int val;

  • C++实现LeetCode(141.单链表中的环)

    C++实现LeetCode(141.单链表中的环)

    [LeetCode] 141. Linked List Cycle 单链表中的环 Given a linked list, determine if it has a cycle in it. To represent a cycle in the given linked list, we use an integer pos which represents the position (0-indexed) in the linked list where tail connects to.

  • C++实现LeetCode(111.二叉树的最小深度)

    [LeetCode] 111. Minimum Depth of Binary Tree 二叉树的最小深度 Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. Note: A leaf is a node with no child

  • C++实现LeetCode(115.不同的子序列)

    [LeetCode] 115. Distinct Subsequences 不同的子序列 Given a string S and a string T, count the number of distinct subsequences of S which equals T. A subsequence of a string is a new string which is formed from the original string by deleting some (can be n

  • C++实现LeetCode(110.平衡二叉树)

    [LeetCode] 110.Balanced Binary Tree 平衡二叉树 Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the depth of the two subtrees of everynode never differ by more t

  • C++实现LeetCode(143.链表重排序)

    [LeetCode] 143.Reorder List 链表重排序 Given a singly linked list L: L0→L1→-→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→- You may not modify the values in the list's nodes, only nodes itself may be changed. Example 1: Given 1->2->3->4, reorder it t

  • C++实现LeetCode(121.买卖股票的最佳时间)

    [LeetCode] 121.Best Time to Buy and Sell Stock 买卖股票的最佳时间 Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the sto

  • C++实现LeetCode(188.买卖股票的最佳时间之四)

    [LeetCode] 188.Best Time to Buy and Sell Stock IV 买卖股票的最佳时间之四 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. Note: You m

  • C++实现LeetCode(122.买股票的最佳时间之二)

    [LeetCode] 122.Best Time to Buy and Sell Stock II 买股票的最佳时间之二 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie

  • C++实现LeetCode(309.买股票的最佳时间含冷冻期)

    [LeetCode] 309.Best Time to Buy and Sell Stock with Cooldown 买股票的最佳时间含冷冻期 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as

  • python买卖股票的最佳时机（基于贪心/蛮力算法）

    python买卖股票的最佳时机（基于贪心/蛮力算法）

    开始刷leetcode算法题 今天做的是"买卖股票的最佳时机" 题目要求 给定一个数组,它的第 i 个元素是一支给定股票第 i 天的价格. 设计一个算法来计算你所能获取的最大利润.你可以尽可能地完成更多的交易(多次买卖一支股票). 注意:你不能同时参与多笔交易(你必须在再次购买前出售掉之前的股票). 看到这个题目 最初的想法是蛮力法 通过两层循环 不断计算不同天之间的利润及利润和 下面上代码 class Solution(object): def maxProfit(self, pri

  • C++实现LeetCode(123.买股票的最佳时间之三)

    [LeetCode] 123.Best Time to Buy and Sell Stock III 买股票的最佳时间之三 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You

  • 基于java计算买卖股票的最佳时机

    基于java计算买卖股票的最佳时机

    这篇文章主要介绍了基于java计算买卖股票的最佳时机,文中通过示例代码介绍的非常详细,对大家的学习或者工作具有一定的参考学习价值,需要的朋友可以参考下 问题: 可以将问题转化为如下图所示,即求多个累计的收入差 分析: 如果当前位置i的价格比i+1的价格高,则当前不是买入点,则继续判断下一个位置, 如果当前位置i的价格比i+1的价格低,并且i+1仍比i+1+1低,则在当前位置买入,知道i+n比i+n+1大时,卖出. 继续下一轮判断 package com.example.demo; public

  • C++ LeeCode题目:比特位计数和买卖股票的最佳时机

    C++ LeeCode题目:比特位计数和买卖股票的最佳时机

    目录 一.比特位计数 一.题目 二.代码 二.买卖股票的最佳时机 一.题目 二.代码 总结 一.比特位计数 一.题目 二.代码 十进制转二进制-百度百科 class Solution { public: vector<int> countBits(int n) { vector<int> num; for(int i=0;i<=n;i++){//遍历[0,n],计算每个值对应二进制1的个数 num.push_back(countOne(i)); } return num; }

  • Java通过动态规划设计股票买卖最佳时机

    Java通过动态规划设计股票买卖最佳时机

    目录 买卖股票的最佳时机 动态规划 买卖股票的最佳时机 给定一个数组 prices ,它的第 i 个元素 prices[i] 表示一支给定股票第 i 天的价格.你只能选择 某一天 买入这只股票,并选择在 未来的某一个不同的日子 卖出该股票.设计一个算法来计算你所能获取的最大利润.返回你可以从这笔交易中获取的最大利润.如果你不能获取任何利润,返回 0 . 示例: 链接:https://leetcode.cn/problems/best-time-to-buy-and-sell-stock 动态规划

  • JavaScript股票的动态买卖规划实例分析下篇

    目录 1. 最佳买卖股票时机含冷冻期 题目描述 题解 2. 买卖股票的最佳时机 III 题目描述 题解 1. 最佳买卖股票时机含冷冻期 题目描述 给定一个整数数组prices,其中第prices[i]表示第i天的股票价格 . 设计一个算法计算出最大利润.在满足以下约束条件下,你可以尽可能地完成更多的交易(多次买卖一支股票): 卖出股票后,你无法在第二天买入股票 (即冷冻期为 1 天). 注意:你不能同时参与多笔交易(你必须在再次购买前出售掉之前的股票). 示例 1: 输入: prices = [

随机推荐