python 日期操作类代码

完整代码

# -*- coding: utf-8 -*-

'''获取当前日期前后N天或N月的日期'''

from time import strftime, localtime
from datetime import timedelta, date
import calendar

year = strftime("%Y",localtime())
mon = strftime("%m",localtime())
day = strftime("%d",localtime())
hour = strftime("%H",localtime())
min = strftime("%M",localtime())
sec = strftime("%S",localtime())

def today():
 '''''
 get today,date format="YYYY-MM-DD"
 '''''
 return date.today()

def todaystr():
 '''
 get date string, date format="YYYYMMDD"
 '''
 return year+mon+day

def datetime():
 '''''
 get datetime,format="YYYY-MM-DD HH:MM:SS"
 '''
 return strftime("%Y-%m-%d %H:%M:%S",localtime())

def datetimestr():
 '''''
 get datetime string
 date format="YYYYMMDDHHMMSS"
 '''
 return year+mon+day+hour+min+sec

def get_day_of_day(n=0):
 '''''
 if n>=0,date is larger than today
 if n<0,date is less than today
 date format = "YYYY-MM-DD"
 '''
 if(n<0):
  n = abs(n)
  return date.today()-timedelta(days=n)
 else:
  return date.today()+timedelta(days=n)

def get_days_of_month(year,mon):
 '''''
 get days of month
 '''
 return calendar.monthrange(year, mon)[1] 

def get_firstday_of_month(year,mon):
 '''''
 get the first day of month
 date format = "YYYY-MM-DD"
 '''
 days="01"
 if(int(mon)<10):
  mon = "0"+str(int(mon))
 arr = (year,mon,days)
 return "-".join("%s" %i for i in arr) 

def get_lastday_of_month(year,mon):
 '''''
 get the last day of month
 date format = "YYYY-MM-DD"
 '''
 days=calendar.monthrange(year, mon)[1]
 mon = addzero(mon)
 arr = (year,mon,days)
 return "-".join("%s" %i for i in arr) 

def get_firstday_month(n=0):
 '''''
 get the first day of month from today
 n is how many months
 '''
 (y,m,d) = getyearandmonth(n)
 d = "01"
 arr = (y,m,d)
 return "-".join("%s" %i for i in arr) 

def get_lastday_month(n=0):
 '''''
 get the last day of month from today
 n is how many months
 '''
 return "-".join("%s" %i for i in getyearandmonth(n)) 

def getyearandmonth(n=0):
 '''''
 get the year,month,days from today
 befor or after n months
 '''
 thisyear = int(year)
 thismon = int(mon)
 totalmon = thismon+n
 if(n>=0):
  if(totalmon<=12):
   days = str(get_days_of_month(thisyear,totalmon))
   totalmon = addzero(totalmon)
   return (year,totalmon,days)
  else:
   i = totalmon/12
   j = totalmon%12
   if(j==0):
    i-=1
    j=12
   thisyear += i
   days = str(get_days_of_month(thisyear,j))
   j = addzero(j)
   return (str(thisyear),str(j),days)
 else:
  if((totalmon>0) and (totalmon<12)):
   days = str(get_days_of_month(thisyear,totalmon))
   totalmon = addzero(totalmon)
   return (year,totalmon,days)
  else:
   i = totalmon/12
   j = totalmon%12
   if(j==0):
    i-=1
    j=12
   thisyear +=i
   days = str(get_days_of_month(thisyear,j))
   j = addzero(j)
   return (str(thisyear),str(j),days) 

def addzero(n):
 '''''
 add 0 before 0-9
 return 01-09
 '''
 nabs = abs(int(n))
 if(nabs<10):
  return "0"+str(nabs)
 else:
  return nabs 

def get_today_month(n=0):
 '''''
 获取当前日期前后N月的日期
 if n>0, 获取当前日期前N月的日期
 if n<0, 获取当前日期后N月的日期
 date format = "YYYY-MM-DD"
 '''
 (y,m,d) = getyearandmonth(n)
 arr=(y,m,d)
 if(int(day)<int(d)):
  arr = (y,m,day)
 return "-".join("%s" %i for i in arr) 

if __name__=="__main__":
 print today()
 print todaystr()
 print datetime()
 print datetimestr()
 print get_day_of_day(20)
 print get_day_of_day(-3)
 print get_today_month(-3)
 print get_today_month(3)

这篇关于python 日期操作类的文章就介绍到这，里面涉及了python日期操作的一些基础知识。

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