C语言实现俄罗斯方块小游戏

C语言实现俄罗斯方块小游戏的制作代码，具体内容如下

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h> 

#define TTY_PATH "/dev/tty"
#define STTY_ON "stty raw -echo -F"
#define STTY_OFF "stty -raw echo -F" 

int map[21][14];
char direct; 

int node[7][4][16]={
  {{0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},//长方形
   {0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0},
   {0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},
   {0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0}},
  {{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},//正方形
   {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},
   {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},
   {1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0}},
  {{0,1,0,0,1,1,1,0,0,0,0,0,0,0,0,0},//3边加一中点
   {0,1,0,0,0,1,1,0,0,1,0,0,0,0,0,0},
   {0,0,0,0,1,1,1,0,0,1,0,0,0,0,0,0},
   {0,1,0,0,1,1,0,0,0,1,0,0,0,0,0,0}},
  {{0,1,1,0,0,1,0,0,0,1,0,0,0,0,0,0},//右锄头型
   {0,0,0,0,1,1,1,0,0,0,1,0,0,0,0,0},
   {0,1,0,0,0,1,0,0,1,1,0,0,0,0,0,0},
   {1,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0}},
  {{1,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0},//左锄头型
   {0,0,1,0,1,1,1,0,0,0,0,0,0,0,0,0},
   {0,1,0,0,0,1,0,0,0,1,1,0,0,0,0,0},
   {0,0,0,0,1,1,1,0,1,0,0,0,0,0,0,0}},
  {{0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},//右曲折型
   {0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0},
   {0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},
   {0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0}},
  {{0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},//左曲折型
   {1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0},
   {0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},
   {1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0}}
  }; 

typedef struct block
{
 int x;
 int y;
 int blockType;
 int blockDirect;
}Block;
Block bl; 

void init_map()//初始化边框
{
 int i,j;
 for(i=0; i<21; i++)
  for(j=0; j<14; j++)
  {
   if(j==0 || j==13)
    map[i][j] = 200;
   else if(i==20)
    map[i][j] = 201;
   else
    map[i][j] = 0;
  }
}
void new_block()//生成随机的俄罗斯方块
{
 int blockType = rand()%7;
 int blockDirect = rand()%4;
 int x = 1;
 int y = 5;
 bl.x = x;
 bl.y = y;
 bl.blockType = blockType;
 bl.blockDirect = blockDirect;
} 

void input()//将移动后的俄罗斯方块，导入地图中作标记
{
 int i, j;
 for(i=0; i<4; i++)
  for(j=0; j<4; j++)
   if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
   {
    map[bl.x+i][bl.y+j] = 1;
   }
}
void output()//移动时，将之前俄罗斯方块在地图信息清空。
{
 int i, j;
 for(i=0; i<4; i++)
  for(j=0; j<4; j++)
   if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
   {
    map[bl.x+i][bl.y+j] = 0;
   }
} 

void change()//俄罗斯方格在碰撞后融入，固定
{
 int i, j;
 for(i=0; i<4; i++)
  for(j=0; j<4; j++)
   if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
   {
    map[bl.x+i][bl.y+j] = 10;
   }
 for(j=1; j<13; j++)
  if(map[5][j] == 10)
  {
   system("clear");
   printf("game over !!!!!!!!!\n");
   exit(1);
  }
} 

void print_map()//打印地图，显示信息
{
 int i,j;
 for(i=5; i<21; i++)
 {
  for(j=0; j<14; j++)
  {
   if(map[i][j]==200)//左右边界
    printf("#");
   else if(map[i][j]==201)//下边界
    printf(" # ");
   else if(map[i][j]==0)//空白地
    printf(" ");
   else if(map[i][j]==1)//移动的俄罗斯方块
    printf(" * ");
   else if(map[i][j]==10)//固定的俄罗斯方块
    printf(" @ ");
  }
  printf("\n");
 }
}
void delLine(int n)//消行
{
 int i,j;
 for(j = 1; j<13; j++)
  map[n][j] = 0;
 for(i = n; i>5 ; i--)
  for(j = 1; j<13; j++)
  if(map[i-1][j] != 1)
  map[i][j] = map[i-1][j];
} 

void isFillLine()//是否满足消行条件
{ 

 int i,j;
 int fals;
 for(i=19; i>5; i--)
 {
  fals = 1;
  for(j=1; j<13; j++)
  {
   if(map[i][j] != 10)
   {
    fals = 0;
    continue;
   }
  }
  if(fals)
  {
   delLine(i);
  }
 }
}
void down()//下移
{
 int i, j;
 int fale = 1;
 for(i=3; i>=0; i--)
  for(j=0; j<4; j++)
   if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)
    if(map[bl.x+i+1][bl.y+j] == 10 || map[bl.x+i+1][bl.y+j] == 201)
    {
     change();
     fale = 0;
     new_block();
     isFillLine();
     return;
    }
 if(fale)
 {
  output();
  bl.x += 1;
  input();
 } 

}
void right()//右移
{
 int i, j;
 int fale = 1;
 for(i=3; i>=0; i--)
  for(j=0; j<4; j++)
   if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)
    if(map[bl.x+i][bl.y+j+1] == 10 || map[bl.x+i][bl.y+j+1] == 200)
    {
     fale = 0;
     return;
    }
 if(fale)
 {
  output();
  bl.y += 1;
  input();
 } 

}
void left()//左移
{
 int i, j;
 int fale = 1;
 for(i=3; i>=0; i--)
  for(j=0; j<4; j++)
   if(node[bl.blockType][bl.blockDirect][i*4+j] == 1)
    if(map[bl.x+i][bl.y+j-1] == 10 || map[bl.x+i][bl.y+j-1] == 200)
    {
     fale = 0;
     return;
    }
 if(fale)
 {
  output();
  bl.y -= 1;
  input();
 } 

} 

void change_block()//俄罗斯方块变形
{
 int i,j;
 output();
 int fals = 1;
 bl.blockDirect += 1;
 bl.blockDirect %= 4;
 for(i=0; i<4; i++)
  for(j=0; j<4; j++)
  if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
   if(map[bl.x+i][bl.y+j] != 0 )
   {
    fals = 0;
    break;
   }
 if(fals)
 {
  input();
 }else
 {
  bl.blockDirect -= 1;
  input();
 }
} 

char in_direct()//非堵塞输入
{
 fd_set fd;
 struct timeval tv;
 char ch;
 FD_ZERO(&fd);
 FD_SET(0, &fd);
 tv.tv_sec = 0;
 tv.tv_usec = 10;
 if(select(1, &fd ,NULL, NULL, &tv) > 0)
 {
   ch = getchar();
 }
 return ch;
}
int main()//q 退出游戏，a,d 左右移动，空格变形
{
 srand(time(NULL));
 init_map();
 new_block();
 input();
 char ch;
 int num = 0;
 while(1)
 {
  usleep(500000);
  system(STTY_ON TTY_PATH);
  ch = in_direct();
  system(STTY_OFF TTY_PATH);
  system("clear");
  if(ch == 'a' && num <= 1)
  {
   left();
   print_map();
   num++;
   continue;
  }else if(ch == 'd' && num <= 1)
  {
   right();
   print_map();
   num++;
   continue;
  }else if(ch == ' ' && num <= 1 )
  {
   change_block();
   print_map();
   num++;
   continue;
  }else if(ch == 'q')
  {
   system("clear");
   printf("gave over!!!!!\n");
   exit(0);
  }
  down();
  print_map();
  num = 0; 

 }
 return 0;
}

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