Swift中字典与JSON转换的方法
Swift中经常会遇到字典和字符串的相互转换,因此可以转换可以封装起来,转换代码如下:
func convertStringToDictionary(text: String) -> [String:AnyObject]? { if let data = text.data(using: String.Encoding.utf8) { do { return try JSONSerialization.jsonObject(with: data, options: [JSONSerialization.ReadingOptions.init(rawValue: 0)]) as? [String:AnyObject] } catch let error as NSError { print(error) } } return nil } func convertDictionaryToString(dict:[String:AnyObject]) -> String { var result:String = "" do { //如果设置options为JSONSerialization.WritingOptions.prettyPrinted,则打印格式更好阅读 let jsonData = try JSONSerialization.data(withJSONObject: dict, options: JSONSerialization.WritingOptions.init(rawValue: 0)) if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) { result = JSONString } } catch { result = "" } return result } func convertArrayToString(arr:[AnyObject]) -> String { var result:String = "" do { let jsonData = try JSONSerialization.data(withJSONObject: arr, options: JSONSerialization.WritingOptions.init(rawValue: 0)) if let JSONString = String(data: jsonData, encoding: String.Encoding.utf8) { result = JSONString } } catch { result = "" } return result }
实际测试:
let jsonText:String = "{\"order_info\":[{\"order_id\":\"1479828084819597144\",\"channel\":\"ios\",\"product_id\":\"02\"},{\"order_id\":\"1479828084819597144\",\"channel\":\"ios\",\"product_id\":\"02\"}]}" let dict = self.convertStringToDictionary(text: jsonText) print("字符串转换之后的字典:\(dict!)") var dictionaryOrArray : [String: AnyObject] = [:] dictionaryOrArray["a\"b"] = "cd" as AnyObject? dictionaryOrArray["strings"] = ["string", "another"] as AnyObject? dictionaryOrArray["keywdict"] = [ "anotherKey": 100, "Key2": "Val2"] as AnyObject? dictionaryOrArray["numbers"] = [ 1, 2, 3] as AnyObject? dictionaryOrArray["bools"] = [ true, false] as AnyObject? let convertResult:String = self.convertDictionaryToString(dict: dictionaryOrArray) print("字典转换之后的字符串:\(convertResult)") let array:[String] = ["FlyElephant","keso"] print("数组转换之后的数组:\(self.convertArrayToString(arr: array as [AnyObject]))")
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