使用python 写一个静态服务(实战)
师父布置的任务,让我写一个服务练练手,搞清楚socket的原理和过程后跑了一个小demo,很有成就感,代码内容也比较清晰易懂,很有教育启发意义。
代码
# coding:utf-8 import socket from multiprocessing import Process HTML_ROOT_DIR = "" def handle_client(client_socket): """处理客户端请求""" # 获取客户端请求数据 request_data = client_socket.recv(1024) print("request data:", request_data) # 构造响应数据 response_start_line = "HTTP/1.1 200 OK\r\n" response_headers = "Server: My server\r\n" response_body = "hello itcast" response = response_start_line + response_headers + "\r\n" + response_body print("response data:", response) # 向客户端返回响应数据 client_socket.send(bytes(response, "utf-8")) # 关闭客户端连接 client_socket.close() if __name__=="__main__": server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM) server_socket.bind(("", 8000)) server_socket.listen(120) while True: client_socket, client_address = server_socket.accept() # print("[%s, %s]用户连接上了"%client_addrest[0],client_address[1]) print("[%s, %s]用户连接上了" % client_address) handle_client_process = Process(target=handle_client, args=(client_socket,)) handle_client_process.start() client_socket.close()
运行后在浏览器输入:127.0.0.1:8000
http页面显示如下:
控制台输出:
[127.0.0.1, 50066]用户连接上了 request data: b'GET / HTTP/1.1\r\nHost: 127.0.0.1:8000\r\nUpgrade-Insecure-Requests: 1\r\nAccept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8\r\nUser-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_1) AppleWebKit/604.3.5 (KHTML, like Gecko) Version/11.0.1 Safari/604.3.5\r\nAccept-Language: zh-cn\r\nAccept-Encoding: gzip, deflate\r\nConnection: keep-alive\r\n\r\n' response data: HTTP/1.1 200 OK Server: My server hello itcast [127.0.0.1, 50067]用户连接上了 request data: b'GET /favicon.ico HTTP/1.1\r\nHost: 127.0.0.1:8000\r\nConnection: keep-alive\r\nAccept: */*\r\nUser-Agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10_13_1) AppleWebKit/604.3.5 (KHTML, like Gecko) Version/11.0.1 Safari/604.3.5\r\nAccept-Language: zh-cn\r\nReferer: http://127.0.0.1:8000/\r\nAccept-Encoding: gzip, deflate\r\n\r\n' response data: HTTP/1.1 200 OK Server: My server hello itcast
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