C++实现LeetCode(163.缺失区间)

[LeetCode] 163. Missing Ranges 缺失区间

Given a sorted integer array nums, where the range of elements are in the inclusive range [lower, upper], return its missing ranges.

Example:

Input: nums = [0, 1, 3, 50, 75], lower = 0 and upper = 99,
Output: ["2", "4->49", "51->74", "76->99"]

这道题让我们求缺失区间，跟之前那道 Summary Ranges 很类似，给了一个空间的范围 [lower upper]，缺失的区间的范围需要在给定的区间范围内。遍历 nums 数组，假如当前数字 num 大于 lower，说明此时已经有缺失区间，至少缺失一个 lower 数字，此时若 num-1 大于 lower，说明缺失的是一个区间 [lower, num-1]，否则就只加入一个数字即可。由于 OJ 之后加入了许多 tricky 的 test cases，使得论坛上很多解法都 fail 了。其实很多是跪在了整型溢出，当数组中有整型最大值时，此时 lower 更新为 num+1 时就会溢出，所以在更新之前要先判断一下，若 num 已经是整型最大值了，直接返回结果 res 即可；否则才更新 lower 继续循环。for 循环退出后，此时可能还存在缺失区间，就是此时 lower 还小于等于 upper 时，可以会缺失 lower 这个数字，或者 [lower, upper] 区间，最后补上这个区间就可以通过啦，参见代码如下：

class Solution {
public:
    vector<string> findMissingRanges(vector<int>& nums, int lower, int upper) {
        vector<string> res;
        for (int num : nums) {
            if (num > lower) res.push_back(to_string(lower) + (num - 1 > lower ? ("->" + to_string(num - 1)) : ""));
            if (num == upper) return res;
            lower = num + 1;
        }
        if (lower <= upper) res.push_back(to_string(lower) + (upper > lower ? ("->" + to_string(upper)) : ""));
        return res;
    }
};

Github 同步地址：

https://github.com/grandyang/leetcode/issues/163

类似题目：

Summary Ranges

参考资料：

https://leetcode.com/problems/missing-ranges/

https://leetcode.com/problems/missing-ranges/discuss/50468/Accepted-Java-solution-8-lines-and-0ms

到此这篇关于C++实现LeetCode(163.缺失区间)的文章就介绍到这了,更多相关C++实现缺失区间内容请搜索我们以前的文章或继续浏览下面的相关文章希望大家以后多多支持我们！

赞 (0)

相关推荐

  • C++实现LeetCode(159.最多有两个不同字符的最长子串)

    [LeetCode] 159. Longest Substring with At Most Two Distinct Characters 最多有两个不同字符的最长子串 Given a string s , find the length of the longest substring t  that contains at most 2 distinct characters. Example 1: Input: "eceba" Output: 3 Explanation: ti

  • C++实现LeetCode(158.用Read4来读取N个字符之二 - 多次调用)

    [LeetCode] 158. Read N Characters Given Read4 II - Call multiple times 用Read4来读取N个字符之二 - 多次调用 Given a file and assume that you can only read the file using a given method read4, implement a method read to read n characters. Your method read may be ca

  • C++实现LeetCode(161.一个编辑距离)

    [LeetCode] 161. One Edit Distance 一个编辑距离 Given two strings s and t, determine if they are both one edit distance apart. Note:  There are 3 possiblities to satisify one edit distance apart: Insert a character into s to get t Delete a character from s 

  • C++实现LeetCode(904.水果装入果篮)

    [LeetCode] 904. Fruit Into Baskets 水果装入果篮 In a row of trees, the `i`-th tree produces fruit with type `tree[i]`. You start at any tree of your choice, then repeatedly perform the following steps: Add one piece of fruit from this tree to your baskets.

  • C++实现LeetCode(160.求两个链表的交点)

    [LeetCode] 160.Intersection of Two Linked Lists 求两个链表的交点 Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A:          a1 → a2 c1 → c2 → c3             B:     b1

  • C++实现LeetCode(228.总结区间)

    [LeetCode] 228.Summary Ranges 总结区间 Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input:  [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous ran

  • C++实现LeetCode(157.用Read4来读取N个字符)

    [LeetCode] 157. Read N Characters Given Read4 用Read4来读取N个字符 Given a file and assume that you can only read the file using a given method read4, implement a method to read n characters. Method read4: The API read4 reads 4 consecutive characters from t

  • C++实现LeetCode(162.求数组的局部峰值)

    [LeetCode] 162.Find Peak Element 求数组的局部峰值 A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that c

  • C++实现LeetCode(163.缺失区间)

    [LeetCode] 163. Missing Ranges 缺失区间 Given a sorted integer array nums, where the range of elements are in the inclusive range [lower, upper], return its missing ranges. Example: Input: nums = [0, 1, 3, 50, 75], lower = 0 and upper = 99, Output: ["2&q

  • C++实现LeetCode(57.插入区间)

    [LeetCode] 57. Insert Interval 插入区间 Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: int

  • C++实现LeetCode(56.合并区间)

    [LeetCode] 56. Merge Intervals 合并区间 Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into

  • C++实现LeetCode(41.首个缺失的正数)

    [LeetCode] 41. First Missing Positive 首个缺失的正数 Given an unsorted integer array, find the smallest missing positive integer. Example 1: Input: [1,2,0] Output: 3 Example 2: Input: [3,4,-1,1] Output: 2 Example 3: Input: [7,8,9,11,12] Output: 1 Note: Your

  • Python实现输出某区间范围内全部素数的方法

    Python实现输出某区间范围内全部素数的方法

    本文实例讲述了Python实现输出某区间范围内全部素数的方法.分享给大家供大家参考,具体如下: # -*- coding: utf-8 -*- # 简述:区间范围101-200 # 要求:判断这个区间内有多少个素数,并逐一输出. def prime(m,n): list1=[] list2=[] for i in range(m,n+1): list1.append(i) for j in range(2,m/2): if i%j==0: list2.append(i) break #print

  • C++实现LeetCode(132.拆分回文串之二)

    [LeetCode] 132.Palindrome Partitioning II 拆分回文串之二 Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. Example: Input: "aab" Output: 1 Explan

  • C++实现LeetCode(131.拆分回文串)

    [LeetCode] 131.Palindrome Partitioning 拆分回文串 Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. Example: Input: "aab" Output: [ ["aa","b"

  • C++实现LeetCode(5.最长回文子串)

    [LeetCode] 5. Longest Palindromic Substring 最长回文子串 Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: "babad" Output: "bab" Note: "aba" is als

  • C++实现LeetCode(36.验证数独)

    C++实现LeetCode(36.验证数独)

    [LeetCode] 36. Valid Sudoku 验证数独 Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules: Each row must contain the digits 1-9without repetition. Each column must contain the digits 1-9 wi

随机推荐