详解Go语言如何实现二叉树遍历
目录
- 1. 二叉树的定义
- 2. 前序遍历
- 3. 中序遍历
- 4. 后序遍历
1. 二叉树的定义
二叉树需满足的条件
① 本身是有序树
② 树中包含的各个节点的长度不能超过2,即只能是0、1或者2
2. 前序遍历
前序遍历二叉树的顺序:根——》左——》右
package main import "fmt" //定义结构体 type Student struct { Name string Age int Score float32 left *Student //左子树指针 right *Student //右子树指针 } //二叉树定义 func main() { //根节点 var root Student root.Name = "root" root.Age = 18 root.Score = 88 //一级左子树 var left1 Student left1.Name = "left1" left1.Age = 20 left1.Score = 80 root.left = &left1 //一级右子树 var right1 Student right1.Name = "right1" right1.Age = 22 right1.Score = 100 root.right = &right1 //二级左子树 var left2 Student left2.Name = "left2" left2.Age = 25 left2.Score = 90 left1.left = &left2 //调用遍历函数 Req(&root) } //递归算法遍历整个二叉树 func Req(tmp *Student) { for tmp == nil { return } fmt.Println(tmp) //遍历左子树 Req(tmp.left) //遍历右子树 Req(tmp.right) }
输出结果如下
&{root 18 88 0xc0000c0480 0xc0000c04b0}
&{left1 20 80 0xc0000c04e0 <nil>}
&{left2 25 90 <nil> <nil>}
&{right1 22 100 <nil> <nil>}
3. 中序遍历
中序遍历:左——》根——》右
package main import "fmt" //定义结构体 type Student struct { Name string Age int Score float32 left *Student //左子树指针 right *Student //右子树指针 } //二叉树定义 func main() { //根节点 var root Student root.Name = "root" root.Age = 18 root.Score = 88 //一级左子树 var left1 Student left1.Name = "left1" left1.Age = 20 left1.Score = 80 root.left = &left1 //一级右子树 var right1 Student right1.Name = "right1" right1.Age = 22 right1.Score = 100 root.right = &right1 //二级左子树 var left2 Student left2.Name = "left2" left2.Age = 25 left2.Score = 90 left1.left = &left2 //调用遍历函数 Req(&root) } //递归算法遍历整个二叉树 func Req(tmp *Student) { for tmp == nil { return } //遍历左子树 Req(tmp.left) //输出root节点 fmt.Println(tmp) //遍历右子树 Req(tmp.right) }
输出结果如下
&{left2 25 90 <nil> <nil>}
&{left1 20 80 0xc000114510 <nil>}
&{root 18 88 0xc0001144b0 0xc0001144e0}
&{right1 22 100 <nil> <nil>}
4. 后序遍历
后序遍历:左——》右——》根
package main import "fmt" //定义结构体 type Student struct { Name string Age int Score float32 left *Student //左子树指针 right *Student //右子树指针 } //二叉树定义 func main() { //根节点 var root Student root.Name = "root" root.Age = 18 root.Score = 88 //一级左子树 var left1 Student left1.Name = "left1" left1.Age = 20 left1.Score = 80 root.left = &left1 //一级右子树 var right1 Student right1.Name = "right1" right1.Age = 22 right1.Score = 100 root.right = &right1 //二级左子树 var left2 Student left2.Name = "left2" left2.Age = 25 left2.Score = 90 left1.left = &left2 //调用遍历函数 Req(&root) } //递归算法遍历整个二叉树 func Req(tmp *Student) { for tmp == nil { return } //遍历左子树 Req(tmp.left) //遍历右子树 Req(tmp.right) //输出root节点 fmt.Println(tmp) }
输出结果如下
&{left2 25 90 <nil> <nil>}
&{left1 20 80 0xc0000c04e0 <nil>}
&{right1 22 100 <nil> <nil>}
&{root 18 88 0xc0000c0480 0xc0000c04b0}
到此这篇关于详解Go语言如何实现二叉树遍历的文章就介绍到这了,更多相关Go语言二叉树遍历内容请搜索我们以前的文章或继续浏览下面的相关文章希望大家以后多多支持我们!
赞 (0)