python 自动监控最新邮件并读取的操作

我就废话不多说了，大家还是直接看代码吧~

#zmail库：可以用几行代码帮我们收取一封邮件
import zmail
#输入账号和密码
server=zmail.server('13163964546@qq.com','jie110341')
#获取最新的一封邮件
mail=server.get_latest()
#读取邮件
#zmail.show(mail)
#读取邮件的部分内容
print(mail['subject'])
......
#读取附件 邮件 存放路径 如果有同名文件则覆盖
zmail.save_acctachment(mail,target_path=None,overwrite=True)

需要在电脑上下载zmail库

补充：Python邮箱实施监控电脑

我就废话不多说了，大家还是直接看代码吧~

import smtplib
import poplib
import email
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.header import decode_header
def send_email(account, password, email_title, send_text="", file_names=None, file_dir="."):
  msg = MIMEMultipart()
  # msg = MIMEText(HTML, 'html') -- 只能发送文本内容
  content = MIMEText(send_text, "plain", "utf-8")
  msg.attach(content)
  # 文件类型
  if isinstance(file_names, list):
    for file_name in file_names:
      send_file_path = file_dir + "/" + file_name
      part = MIMEApplication(open(send_file_path, 'rb').read())
      part.add_header('Content-Disposition', 'attachment', filename=file_name)
      msg.attach(part)
  elif isinstance(file_names, str):
    send_file_path = file_dir + "/" + file_names
    part = MIMEApplication(open(send_file_path, 'rb').read())
    part.add_header('Content-Disposition', 'attachment', filename=file_names)
    msg.attach(part)
  # msg['from'],msg['to']接收端显示的发件人与收件人
  msg['from'] = "奥巴马@163.com"
  msg['to'] = account
  msg['subject'] = email_title
  try:
    server = smtplib.SMTP()
    server.connect('smtp.163.com')
    server.login(account, password)
    # from_addr:发送地址; to_addrs:接收地址(字符串列表)
    server.sendmail(account, msg['to'].split(), msg.as_string())
  except Exception as e:
    print(e)
# 获取邮件标题
def get_email_subject(addr, password):
  # 设置连接网址,获取pop3协议的邮件读取对象
  read = poplib.POP3('pop.163.com', timeout=3600)
  # 输入邮件地址与邮件登录密码
  read.user(addr) # 163邮箱用户名
  read.pass_(password) # 163邮箱设置中的客户端授权密码
  # allEmails = (totalNum, totalSize)
  # 读取邮件信息(邮件总数,邮件尺寸)
  total_num, total_size = read.stat()
  # top(which,howmuch)
  # 获取最新的一封邮件(第几封邮件,获取多少封)
  top_email = read.top(total_num, 1)
  # print("***** start *****\n接收的数据为: {}\n***** end *****\n".format(top_email))
  #
  # print("***** start *****\n[解码前]获取的初始邮件内容: {}\n***** end *****\n".format(top_email[1]))
  # 解码邮件信息，将解码后的邮件信息存入tmp
  tmp = []
  for s in top_email[1]:
    tmp.append(s.decode())
  # print("***** start *****\n[解码后]的邮件内容为: {}\n*****  end  *****\n".format(tmp))
  # 将解码后的邮件内容拼接为字符串
  email_str = '\n'.join(tmp)
  # 将字符串类型解析为Message类型
  message = email.message_from_string(email_str)
  # print("***** start *****\n"
  #    "[解码前]的邮件字符串内容为: [数据类型]{}\n{}\n"
  #    "--------------------------------------------\n"
  #    "[解码后]的邮件字符串内容为: [数据类型]{}\n{}\n"
  #    "***** end *****\n"
  #    .format(type(email_str), email_str, type(message), message))
  # 获取邮件主题
  subject_str = message['subject']
  # print("***** start *****\n[解码前]邮件标题: {}\n***** end *****\n".format(subject_str))
  subject = decode_header(subject_str)
  # print("***** start *****\n[解码后]邮件标题: {}\n***** end *****\n".format(subject))
  content = subject[0][0]
  enc_type = subject[0][1]
  if enc_type:
    subject_decode = content.decode(enc_type)
  else:
    subject_decode = content
  return subject_decode, read, total_num

以上为个人经验，希望能给大家一个参考，也希望大家多多支持我们。如有错误或未考虑完全的地方，望不吝赐教。