MySql如何获取相邻数据
目录
- 如何获取相邻数据
- 同表相邻数据比对查询
- 需求
- SQL
- 解析
- 最终SQL
如何获取相邻数据
因为项目,所以找到了一些资料并且总结了下关于获取相邻数据的方式。
我只找到了以下的...
/*获取id值与5相减绝对值最近的数据,如果有绝对值相同的,相邻的数据优先输出*/ /*ABS(X)其实就是获取绝对值,然后的话order by 后面的1代表着根据select关键字 后的第一个字段进行排序。limit 后面的数字代表着你想查询数据的行数*/ SELECT ABS(cid-5),cname FROM company ORDER BY 1 LIMIT 3
/*获取指定id的上一条记录,我这里是以id=5为例的*/ select cid,cname from company order by cid>=5,cid desc limit 1
/*获取指定id的下一条记录,我这里是以id=5为例的*/ SELECT cid,cname from company order by cid<=5,cid asc limit 1
记录一下,以免以后遇到又不会
同表相邻数据比对查询
需求
我们将会比对相邻的数据,其中value是递增的,但也会存在清零的情况。我们的需求是计算当天的分钟递增量。
SQL
语句中需要解释一下参数
** ctc_etl.1_1_1907/sum.out_2021 :表名**** WHERE item_timestamp > “2021-12-01 00:00:00” AND item_timestamp < “2021-12-02 00:00:00” 是我自己加的筛选条件**
SELECT b.id,( b.item_value - a.item_value ) AS value, b.item_timestamp AS time FROM ( SELECT id,item_value, @num := @num + 1 AS row_number FROM ( SELECT @num := 0 ) r, ctc_etl.`1_1_1907/sum.out_2021` WHERE item_timestamp > "2021-12-01 00:00:00" AND item_timestamp < "2021-12-02 00:00:00" ORDER BY id ) a, ( SELECT id, item_value, item_timestamp, @num2 := @num2 + 1 AS row_number FROM ( SELECT @num2 := 0 ) r2, ctc_etl.`1_1_1907/sum.out_2021` WHERE item_timestamp > "2021-12-01 00:00:00" AND item_timestamp < "2021-12-02 00:00:00" ORDER BY id ) b WHERE a.row_number + 1 = b.row_number;
解析
目前计算的只是每秒的增加量,其次就是存在负数的情况,也就是清零了后一个数比前一个小就造成了负数
最终SQL
SELECT c.id, SUM( c.VALUE ) AS value, DATE_FORMAT( c.time, "%Y-%m-%d %H:%i:00" ) AS time FROM ( SELECT b.id, (b.item_value - a.item_value ) AS value, b.item_timestamp AS time FROM ( SELECT id, item_value, @num := @num + 1 AS row_number FROM ( SELECT @num := 0 ) r, ctc_etl.`1_1_1907/sum.out_2021` WHERE item_timestamp > "2021-12-01 00:00:00" AND item_timestamp < "2021-12-02 00:00:00" ORDER BY id ) a, ( SELECT id, item_value, item_timestamp, @num2 := @num2 + 1 AS row_number FROM ( SELECT @num2 := 0 ) r2, ctc_etl.`1_1_1907/sum.out_2021` WHERE item_timestamp > "2021-12-01 00:00:00" AND item_timestamp < "2021-12-02 00:00:00" ORDER BY id ) b WHERE a.row_number + 1 = b.row_number ) c WHERE c.VALUE > 0 GROUP BY DATE_FORMAT( c.time, "%Y-%m-%d %H:%i:00")
以上为个人经验,希望能给大家一个参考,也希望大家多多支持我们。
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