C++ 实现双向链表的实例
双向链表C++ 的实现
本文是通过C++ 的知识实现数据结构中的双向链表,这里不多说 了,代码注释很清楚,
实现代码:
//double LinkList implement with C++ template #include<iostream> using namespace std; /*template<typename Type> class DBListADT { public: virtual void Append(const Type &)=0; virtual void Insert(const Type &)=0; virtual void Remove(const Type &)=0; }; template<typename T> class DLinkListNode:public DBListADT<typename T>//此处必须为实现的类型,当然以派生类的模板类型也可以,但是不能是Type { public: void Append(const T &);//这边也需要是当前类的类型,不能为Type void Insert(const T &); void Remove(const T &); };*/ template<typename T>class DLinkList; template<typename Type> class DNode { friend class DLinkList<Type>;//指定前需声明 public: DNode(){next=NULL;prior=NULL;} ~DNode(){} private: DNode *next; DNode *prior; Type data; }; template<typename T> class DLinkList { public: DLinkList() { // head=new DNode<T>[sizeof(DNode<T>)]; head=new DNode<T>; } ~DLinkList() { if(head->next==NULL) delete head; else { DNode<T> *p=head->next; DNode<T>*s=NULL; while(p) { s=p->next ; delete p; p=s; } } } void DeleteElement(size_t position) { DNode<T> *p=head->next; size_t index=1; for(;index<position;index++) p=p->next ; if(p==NULL) return ; p->prior ->next =p->next ; p->next ->prior =p->prior ; delete p; } void InsertElement(T data,size_t position); void CreateDLinkList(T a[],int n); void PrintDLinkList(); private: DNode<T> *head; }; template<typename T> void DLinkList<T>:: InsertElement (T data,size_t position) { DNode<T> *p=head->next; size_t index=1; for(;index<position;index++) p=p->next; if(p==NULL) return; //DNode<T> *s=new DNode<T>[sizeof(DNode<T>)]; DNode<T> *s=new DNode<T>; s->data=data; s->next=p; s->prior=p->prior; p->prior->next=s; p->prior=s; } template<typename T> void DLinkList<T>::CreateDLinkList(T a[],int n) { DNode<T>*p=head; DNode<T>*s=NULL; int i=0; for(;i<n;i++) { // s=new DNode<T>[sizeof(DNode)]; s=new DNode<T>; s->data=a[i]; p->next=s; s->prior=p; p=s; } s->next=NULL; } template<typename T>void DLinkList<T>::PrintDLinkList () { DNode<T> *p=head->next; while(p) { cout<<p->data<<endl; p=p->next; } } int main() { int a[10]={1,2,3,4,5,6,7,8,9,10}; DLinkList<int>Dlist; Dlist.CreateDLinkList(a,10); Dlist.DeleteElement (3); Dlist.InsertElement(3,3); Dlist.PrintDLinkList(); return 0; } //double LinkList implement with C++ Class //************************************************************ /*#include<iostream> using namespace std; class Node { friend class List; public: //Node(int a):next(NULL),prior(NULL),data(a){} Node(){} private: Node *next; Node *prior; int data; }; class List { public: List() { cout<<"create head DBLinkList"<<endl; head=new Node[sizeof(Node)]; }; ~List() { if(head->next==NULL) { delete head; } else { Node *p=head->next; Node *s; delete head; while(p) { s=p->next ; delete p; p=s; } } cout<<"destructor called to clear DBLinkList"<<endl; } void CreateDoubleLink(int a[],int n); void DeleteElemData(int position); void InsertElement(int data,int position); void PrintDList(); private: Node *head; }; void List::CreateDoubleLink (int a[],int n) { head->next =NULL; Node *s,*p=head; int i=0; for(;i<n;i++) { s=new Node[sizeof(Node)]; s->data =a[i]; p->next =s; s->prior =p; p=s; } s->next =NULL; } void List::PrintDList() { Node *p=head->next ; while(p) { cout<<p->data <<endl; p=p->next ; } } void List::DeleteElemData(int position) {//可以通过重载delete运算符来达到这个效果,则直接用delete就OK了 Node *p=head->next ; //while(p!=NULL&&p->data !=data) // p=p->next ; int i=1; for(;i<position;i++) p=p->next ; if(p==NULL) return ; p->prior ->next =p->next ; p->next ->prior =p->prior ; delete p; } void List::InsertElement (int data,int position) {//可以重载new运算符来达到这个效果,则直接用new就OK了 Node *p=head->next ; int i=1; for(;i<position;i++) p=p->next ; Node *s=new Node[sizeof(Node)]; s->data =data; s->prior =p->prior ; s->next =p; p->prior ->next =s; p->prior =s; } int main() { List Dlist; int a[10]={1,2,3,4,5,6,7,8,9,10}; Dlist.CreateDoubleLink (a,10); Dlist.DeleteElemData(3); Dlist.InsertElement (3,3); Dlist.PrintDList (); return 0; }*/ //*************************************************************************************
感谢阅读,希望能帮助到大家,谢谢大家对本站的支持!
赞 (0)