Java Web程序中利用Spring框架返回JSON格式的日期
返回Json时格式化日期Date
第一步:创建CustomObjectMapper类
/** * 解决SpringMVC使用@ResponseBody返回json时,日期格式默认显示为时间戳的问题。需配合<mvc:message-converters>使用 */ @Component("customObjectMapper") public class CustomObjectMapper extends ObjectMapper { public CustomObjectMapper() { CustomSerializerFactory factory = new CustomSerializerFactory(); factory.addGenericMapping(Date.class, new JsonSerializer<Date>() { @Override public void serialize(Date value, JsonGenerator jsonGenerator, SerializerProvider provider) throws IOException, JsonProcessingException { SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); jsonGenerator.writeString(sdf.format(value)); } }); this.setSerializerFactory(factory); } }
第二步:配置如下:
<mvc:annotation-driven> <mvc:message-converters> <bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"> <property name="objectMapper" ref="customObjectMapper"></property> </bean> </mvc:message-converters> </mvc:annotation-driven>
效果如下:
格式化前
格式化后
进阶:返回自定义格式日期
使用@ResponseBody时返回json字符串的日期格式。Date类型属性默认返回一个Long型的时间戳,怎样能够返回自定义的日期格式?
解决方案:目前有两种方式实现,
1、局部修改(网上较多,但不推荐);
继承Jackson的抽象类:JsonSerializer<T>,然后在javabean的属性getter()上添加注解@JsonSerialize即可实现。
代码如下:
import java.io.IOException; import java.text.SimpleDateFormat; import java.util.Date; import org.codehaus.jackson.JsonGenerator; import org.codehaus.jackson.JsonProcessingException; import org.codehaus.jackson.map.JsonSerializer; import org.codehaus.jackson.map.SerializerProvider; /** * @description 自定义返回JSON 数据格中日期格式化处理 */ public class CustomDateSerializer extends JsonSerializer<Date> { @Override public void serialize(Date value, JsonGenerator jsonGenerator, SerializerProvider provider) throws IOException, JsonProcessingException { SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); jsonGenerator.writeString(sdf.format(value)); } }
使用方式:
@JsonSerialize(using = CustomDateSerializer.class) public Date getCreateDate() { return createDate; }
2、全局修改(强烈推荐):
MappingJacksonHttpMessageConverter主要通过ObjectMapper来实现返回json字符串。这里我们继承该类,注册一个JsonSerializer<T>。然后在配置文件中注入自定义的ObjectMapper。
代码如下:
import java.io.IOException; import java.text.SimpleDateFormat; import java.util.Date; import org.codehaus.jackson.JsonGenerator; import org.codehaus.jackson.JsonProcessingException; import org.codehaus.jackson.map.JsonSerializer; import org.codehaus.jackson.map.ObjectMapper; import org.codehaus.jackson.map.SerializerProvider; import org.codehaus.jackson.map.ser.CustomSerializerFactory; /** * @description 解决Date类型返回json格式为自定义格式 */ public class CustomObjectMapper extends ObjectMapper { public CustomObjectMapper(){ CustomSerializerFactory factory = new CustomSerializerFactory(); factory.addGenericMapping(Date.class, new JsonSerializer<Date>(){ @Override public void serialize(Date value, JsonGenerator jsonGenerator, SerializerProvider provider) throws IOException, JsonProcessingException { SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); jsonGenerator.writeString(sdf.format(value)); } }); this.setSerializerFactory(factory); } }
spring-servlet.xml中配置:
<mvc:annotation-driven> <mvc:message-converters> <bean class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"> <property name="objectMapper" ref="customObjectMapper"></property> </bean> </mvc:message-converters> </mvc:annotation-driven> <bean id="customObjectMapper" class="com.pmc.dwa.common.custom.CustomObjectMapper"></bean>
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