linux中查询dns示例

dns.c

代码如下:

/*
 * DNS Query Program on Linux
 *
 * Author : ismdeep@live.com
 *
 * */
//Header Files
#include<stdio.h> //printf
#include<string.h> //strlen
#include<stdlib.h> //malloc
#include<sys/socket.h> //you know what this is for
#include<arpa/inet.h> //inet_addr , inet_ntoa , ntohs etc
#include<netinet/in.h>
#include<unistd.h> //getpid

//List of DNS Servers registered on the system
char dns_servers[10][100];
int dns_server_count = 0;
//Types of DNS resource records :)

#define T_A 1 //Ipv4 address
#define T_NS 2 //Nameserver
#define T_CNAME 5 // canonical name
#define T_SOA 6 /* start of authority zone */
#define T_PTR 12 /* domain name pointer */
#define T_MX 15 //Mail server

//Function Prototypes
void ngethostbyname (unsigned char* , int);
void ChangetoDnsNameFormat (unsigned char*,unsigned char*);
unsigned char* ReadName (unsigned char*,unsigned char*,int*);
void get_dns_servers();

//DNS header structure
struct DNS_HEADER
{
 unsigned short id; // identification number

unsigned char rd :1; // recursion desired
 unsigned char tc :1; // truncated message
 unsigned char aa :1; // authoritive answer
 unsigned char opcode :4; // purpose of message
 unsigned char qr :1; // query/response flag

unsigned char rcode :4; // response code
 unsigned char cd :1; // checking disabled
 unsigned char ad :1; // authenticated data
 unsigned char z :1; // its z! reserved
 unsigned char ra :1; // recursion available

unsigned short q_count; // number of question entries
 unsigned short ans_count; // number of answer entries
 unsigned short auth_count; // number of authority entries
 unsigned short add_count; // number of resource entries
};

//Constant sized fields of query structure
struct QUESTION
{
 unsigned short qtype;
 unsigned short qclass;
};

//Constant sized fields of the resource record structure
#pragma pack(push, 1)
struct R_DATA
{
 unsigned short type;
 unsigned short _class;
 unsigned int ttl;
 unsigned short data_len;
};
#pragma pack(pop)

//Pointers to resource record contents
struct RES_RECORD
{
 unsigned char *name;
 struct R_DATA *resource;
 unsigned char *rdata;
};

//Structure of a Query
typedef struct
{
 unsigned char *name;
 struct QUESTION *ques;
} QUERY;

int main( int argc , char *argv[])
{
 unsigned char hostname[100];

//Get the DNS servers from the resolv.conf file
 get_dns_servers();

//Get the hostname from the terminal
 printf("Enter Hostname to Lookup : ");
 scanf("%s" , hostname);

//Now get the ip of this hostname , A record
 ngethostbyname(hostname , T_A);

return 0;
}

/*
 * Perform a DNS query by sending a packet
 * */
void ngethostbyname(unsigned char *host , int query_type)
{
 unsigned char buf[65536],*qname,*reader;
 int i , j , stop , s;

struct sockaddr_in a;

struct RES_RECORD answers[20],auth[20],addit[20]; //the replies from the DNS server
 struct sockaddr_in dest;

struct DNS_HEADER *dns = NULL;
 struct QUESTION *qinfo = NULL;

printf("Resolving %s" , host);

s = socket(AF_INET , SOCK_DGRAM , IPPROTO_UDP); //UDP packet for DNS queries

dest.sin_family = AF_INET;
 dest.sin_port = htons(53);
 dest.sin_addr.s_addr = inet_addr(dns_servers[0]); //dns servers

//Set the DNS structure to standard queries
 dns = (struct DNS_HEADER *)&buf;

dns->id = (unsigned short) htons(getpid());
 dns->qr = 0; //This is a query
 dns->opcode = 0; //This is a standard query
 dns->aa = 0; //Not Authoritative
 dns->tc = 0; //This message is not truncated
 dns->rd = 1; //Recursion Desired
 dns->ra = 0; //Recursion not available! hey we dont have it (lol)
 dns->z = 0;
 dns->ad = 0;
 dns->cd = 0;
 dns->rcode = 0;
 dns->q_count = htons(1); //we have only 1 question
 dns->ans_count = 0;
 dns->auth_count = 0;
 dns->add_count = 0;

//point to the query portion
 qname =(unsigned char*)&buf[sizeof(struct DNS_HEADER)];

ChangetoDnsNameFormat(qname , host);
 qinfo =(struct QUESTION*)&buf[sizeof(struct DNS_HEADER) + (strlen((const char*)qname) + 1)]; //fill it

qinfo->qtype = htons( query_type ); //type of the query , A , MX , CNAME , NS etc
 qinfo->qclass = htons(1); //its internet (lol)

printf("\nSending Packet...");
 if( sendto(s,(char*)buf,sizeof(struct DNS_HEADER) + (strlen((const char*)qname)+1) + sizeof(struct QUESTION),0,(struct sockaddr*)&dest,sizeof(dest)) < 0)
 {
  perror("sendto failed");
 }
 printf("Done");

//Receive the answer
 i = sizeof dest;
 printf("\nReceiving answer...");
 if(recvfrom (s,(char*)buf , 65536 , 0 , (struct sockaddr*)&dest , (socklen_t*)&i ) < 0)
 {
  perror("recvfrom failed");
 }
 printf("Done");

dns = (struct DNS_HEADER*) buf;

//move ahead of the dns header and the query field
 reader = &buf[sizeof(struct DNS_HEADER) + (strlen((const char*)qname)+1) + sizeof(struct QUESTION)];

printf("\nThe response contains : ");
 printf("\n %d Questions.",ntohs(dns->q_count));
 printf("\n %d Answers.",ntohs(dns->ans_count));
 printf("\n %d Authoritative Servers.",ntohs(dns->auth_count));
 printf("\n %d Additional records.\n\n",ntohs(dns->add_count));

//Start reading answers
 stop=0;

for(i=0;i<ntohs(dns->ans_count);i++)
 {
  answers[i].name=ReadName(reader,buf,&stop);
  reader = reader + stop;

answers[i].resource = (struct R_DATA*)(reader);
  reader = reader + sizeof(struct R_DATA);

if(ntohs(answers[i].resource->type) == 1) //if its an ipv4 address
  {
   answers[i].rdata = (unsigned char*)malloc(ntohs(answers[i].resource->data_len));

for(j=0 ; j<ntohs(answers[i].resource->data_len) ; j++)
   {
    answers[i].rdata[j]=reader[j];
   }

answers[i].rdata[ntohs(answers[i].resource->data_len)] = '\0';

reader = reader + ntohs(answers[i].resource->data_len);
  }
  else
  {
   answers[i].rdata = ReadName(reader,buf,&stop);
   reader = reader + stop;
  }
 }

//read authorities
 for(i=0;i<ntohs(dns->auth_count);i++)
 {
  auth[i].name=ReadName(reader,buf,&stop);
  reader+=stop;

auth[i].resource=(struct R_DATA*)(reader);
  reader+=sizeof(struct R_DATA);

auth[i].rdata=ReadName(reader,buf,&stop);
  reader+=stop;
 }

//read additional
 for(i=0;i<ntohs(dns->add_count);i++)
 {
  addit[i].name=ReadName(reader,buf,&stop);
  reader+=stop;

addit[i].resource=(struct R_DATA*)(reader);
  reader+=sizeof(struct R_DATA);

if(ntohs(addit[i].resource->type)==1)
  {
   addit[i].rdata = (unsigned char*)malloc(ntohs(addit[i].resource->data_len));
   for(j=0;j<ntohs(addit[i].resource->data_len);j++)
   addit[i].rdata[j]=reader[j];

addit[i].rdata[ntohs(addit[i].resource->data_len)]='\0';
   reader+=ntohs(addit[i].resource->data_len);
  }
  else
  {
   addit[i].rdata=ReadName(reader,buf,&stop);
   reader+=stop;
  }
 }

//print answers
 printf("\nAnswer Records : %d \n" , ntohs(dns->ans_count) );
 for(i=0 ; i < ntohs(dns->ans_count) ; i++)
 {
  printf("Name : %s ",answers[i].name);

if( ntohs(answers[i].resource->type) == T_A) //IPv4 address
  {
   long *p;
   p=(long*)answers[i].rdata;
   a.sin_addr.s_addr=(*p); //working without ntohl
   printf("has IPv4 address : %s",inet_ntoa(a.sin_addr));
  }

if(ntohs(answers[i].resource->type)==5)
  {
   //Canonical name for an alias
   printf("has alias name : %s",answers[i].rdata);
  }

printf("\n");
 }

//print authorities
 printf("\nAuthoritive Records : %d \n" , ntohs(dns->auth_count) );
 for( i=0 ; i < ntohs(dns->auth_count) ; i++)
 {

printf("Name : %s ",auth[i].name);
  if(ntohs(auth[i].resource->type)==2)
  {
   printf("has nameserver : %s",auth[i].rdata);
  }
  printf("\n");
 }

//print additional resource records
 printf("\nAdditional Records : %d \n" , ntohs(dns->add_count) );
 for(i=0; i < ntohs(dns->add_count) ; i++)
 {
  printf("Name : %s ",addit[i].name);
  if(ntohs(addit[i].resource->type)==1)
  {
   long *p;
   p=(long*)addit[i].rdata;
   a.sin_addr.s_addr=(*p);
   printf("has IPv4 address : %s",inet_ntoa(a.sin_addr));
  }
  printf("\n");
 }
 return;
}

/*
 *
 * */
u_char* ReadName(unsigned char* reader,unsigned char* buffer,int* count)
{
 unsigned char *name;
 unsigned int p=0,jumped=0,offset;
 int i , j;

*count = 1;
 name = (unsigned char*)malloc(256);

name[0]='\0';

//read the names in 3www6google3com format
 while(*reader!=0)
 {
  if(*reader>=192)
  {
   offset = (*reader)*256 + *(reader+1) - 49152; //49152 = 11000000 00000000 ;)
   reader = buffer + offset - 1;
   jumped = 1; //we have jumped to another location so counting wont go up!
  }
  else
  {
   name[p++]=*reader;
  }

reader = reader+1;

if(jumped==0)
  {
   *count = *count + 1; //if we havent jumped to another location then we can count up
  }
 }

name[p]='\0'; //string complete
 if(jumped==1)
 {
  *count = *count + 1; //number of steps we actually moved forward in the packet
 }

//now convert 3www6google3com0 to www.google.com
 for(i=0;i<(int)strlen((const char*)name);i++)
 {
  p=name[i];
  for(j=0;j<(int)p;j++)
  {
   name[i]=name[i+1];
   i=i+1;
  }
  name[i]='.';
 }
 name[i-1]='\0'; //remove the last dot
 return name;
}

/*
 * Get the DNS servers from /etc/resolv.conf file on Linux
 * */
void get_dns_servers()
{
 FILE *fp;
 char line[200] , *p;
 if((fp = fopen("/etc/resolv.conf" , "r")) == NULL)
 {
  printf("Failed opening /etc/resolv.conf file \n");
 }

while(fgets(line , 200 , fp))
 {
  if(line[0] == '#')
  {
   continue;
  }
  if(strncmp(line , "nameserver" , 10) == 0)
  {
   p = strtok(line , " ");
   p = strtok(NULL , " ");

//p now is the dns ip :)
   //????
  }
 }

strcpy(dns_servers[0] , "208.67.222.222");
 strcpy(dns_servers[1] , "208.67.220.220");
}

/*
 * This will convert www.google.com to 3www6google3com
 * got it :)
 * */
void ChangetoDnsNameFormat(unsigned char* dns,unsigned char* host)
{
 int lock = 0 , i;
 strcat((char*)host,".");

for(i = 0 ; i < strlen((char*)host) ; i++)
 {
  if(host[i]=='.')
  {
   *dns++ = i-lock;
   for(;lock<i;lock++)
   {
    *dns++=host[lock];
   }
   lock++; //or lock=i+1;
  }
 }
 *dns++='\0';
}

dns.c

代码如下:

/*
 * DNS Query Program on Linux
 *
 * Author : ismdeep@live.com
 *
 * */
//Header Files
#include<stdio.h> //printf
#include<string.h> //strlen
#include<stdlib.h> //malloc
#include<sys/socket.h> //you know what this is for
#include<arpa/inet.h> //inet_addr , inet_ntoa , ntohs etc
#include<netinet/in.h>
#include<unistd.h> //getpid

//List of DNS Servers registered on the system
char dns_servers[10][100];
int dns_server_count = 0;
//Types of DNS resource records :)

#define T_A 1 //Ipv4 address
#define T_NS 2 //Nameserver
#define T_CNAME 5 // canonical name
#define T_SOA 6 /* start of authority zone */
#define T_PTR 12 /* domain name pointer */
#define T_MX 15 //Mail server

//Function Prototypes
void ngethostbyname (unsigned char* , int);
void ChangetoDnsNameFormat (unsigned char*,unsigned char*);
unsigned char* ReadName (unsigned char*,unsigned char*,int*);
void get_dns_servers();

//DNS header structure
struct DNS_HEADER
{
 unsigned short id; // identification number

unsigned char rd :1; // recursion desired
 unsigned char tc :1; // truncated message
 unsigned char aa :1; // authoritive answer
 unsigned char opcode :4; // purpose of message
 unsigned char qr :1; // query/response flag

unsigned char rcode :4; // response code
 unsigned char cd :1; // checking disabled
 unsigned char ad :1; // authenticated data
 unsigned char z :1; // its z! reserved
 unsigned char ra :1; // recursion available

unsigned short q_count; // number of question entries
 unsigned short ans_count; // number of answer entries
 unsigned short auth_count; // number of authority entries
 unsigned short add_count; // number of resource entries
};

//Constant sized fields of query structure
struct QUESTION
{
 unsigned short qtype;
 unsigned short qclass;
};

//Constant sized fields of the resource record structure
#pragma pack(push, 1)
struct R_DATA
{
 unsigned short type;
 unsigned short _class;
 unsigned int ttl;
 unsigned short data_len;
};
#pragma pack(pop)

//Pointers to resource record contents
struct RES_RECORD
{
 unsigned char *name;
 struct R_DATA *resource;
 unsigned char *rdata;
};

//Structure of a Query
typedef struct
{
 unsigned char *name;
 struct QUESTION *ques;
} QUERY;

int main( int argc , char *argv[])
{
 unsigned char hostname[100];

//Get the DNS servers from the resolv.conf file
 get_dns_servers();

//Get the hostname from the terminal
 printf("Enter Hostname to Lookup : ");
 scanf("%s" , hostname);

//Now get the ip of this hostname , A record
 ngethostbyname(hostname , T_A);

return 0;
}

/*
 * Perform a DNS query by sending a packet
 * */
void ngethostbyname(unsigned char *host , int query_type)
{
 unsigned char buf[65536],*qname,*reader;
 int i , j , stop , s;

struct sockaddr_in a;

struct RES_RECORD answers[20],auth[20],addit[20]; //the replies from the DNS server
 struct sockaddr_in dest;

struct DNS_HEADER *dns = NULL;
 struct QUESTION *qinfo = NULL;

printf("Resolving %s" , host);

s = socket(AF_INET , SOCK_DGRAM , IPPROTO_UDP); //UDP packet for DNS queries

dest.sin_family = AF_INET;
 dest.sin_port = htons(53);
 dest.sin_addr.s_addr = inet_addr(dns_servers[0]); //dns servers

//Set the DNS structure to standard queries
 dns = (struct DNS_HEADER *)&buf;

dns->id = (unsigned short) htons(getpid());
 dns->qr = 0; //This is a query
 dns->opcode = 0; //This is a standard query
 dns->aa = 0; //Not Authoritative
 dns->tc = 0; //This message is not truncated
 dns->rd = 1; //Recursion Desired
 dns->ra = 0; //Recursion not available! hey we dont have it (lol)
 dns->z = 0;
 dns->ad = 0;
 dns->cd = 0;
 dns->rcode = 0;
 dns->q_count = htons(1); //we have only 1 question
 dns->ans_count = 0;
 dns->auth_count = 0;
 dns->add_count = 0;

//point to the query portion
 qname =(unsigned char*)&buf[sizeof(struct DNS_HEADER)];

ChangetoDnsNameFormat(qname , host);
 qinfo =(struct QUESTION*)&buf[sizeof(struct DNS_HEADER) + (strlen((const char*)qname) + 1)]; //fill it

qinfo->qtype = htons( query_type ); //type of the query , A , MX , CNAME , NS etc
 qinfo->qclass = htons(1); //its internet (lol)

printf("\nSending Packet...");
 if( sendto(s,(char*)buf,sizeof(struct DNS_HEADER) + (strlen((const char*)qname)+1) + sizeof(struct QUESTION),0,(struct sockaddr*)&dest,sizeof(dest)) < 0)
 {
  perror("sendto failed");
 }
 printf("Done");

//Receive the answer
 i = sizeof dest;
 printf("\nReceiving answer...");
 if(recvfrom (s,(char*)buf , 65536 , 0 , (struct sockaddr*)&dest , (socklen_t*)&i ) < 0)
 {
  perror("recvfrom failed");
 }
 printf("Done");

dns = (struct DNS_HEADER*) buf;

//move ahead of the dns header and the query field
 reader = &buf[sizeof(struct DNS_HEADER) + (strlen((const char*)qname)+1) + sizeof(struct QUESTION)];

printf("\nThe response contains : ");
 printf("\n %d Questions.",ntohs(dns->q_count));
 printf("\n %d Answers.",ntohs(dns->ans_count));
 printf("\n %d Authoritative Servers.",ntohs(dns->auth_count));
 printf("\n %d Additional records.\n\n",ntohs(dns->add_count));

//Start reading answers
 stop=0;

for(i=0;i<ntohs(dns->ans_count);i++)
 {
  answers[i].name=ReadName(reader,buf,&stop);
  reader = reader + stop;

answers[i].resource = (struct R_DATA*)(reader);
  reader = reader + sizeof(struct R_DATA);

if(ntohs(answers[i].resource->type) == 1) //if its an ipv4 address
  {
   answers[i].rdata = (unsigned char*)malloc(ntohs(answers[i].resource->data_len));

for(j=0 ; j<ntohs(answers[i].resource->data_len) ; j++)
   {
    answers[i].rdata[j]=reader[j];
   }

answers[i].rdata[ntohs(answers[i].resource->data_len)] = '\0';

reader = reader + ntohs(answers[i].resource->data_len);
  }
  else
  {
   answers[i].rdata = ReadName(reader,buf,&stop);
   reader = reader + stop;
  }
 }

//read authorities
 for(i=0;i<ntohs(dns->auth_count);i++)
 {
  auth[i].name=ReadName(reader,buf,&stop);
  reader+=stop;

auth[i].resource=(struct R_DATA*)(reader);
  reader+=sizeof(struct R_DATA);

auth[i].rdata=ReadName(reader,buf,&stop);
  reader+=stop;
 }

//read additional
 for(i=0;i<ntohs(dns->add_count);i++)
 {
  addit[i].name=ReadName(reader,buf,&stop);
  reader+=stop;

addit[i].resource=(struct R_DATA*)(reader);
  reader+=sizeof(struct R_DATA);

if(ntohs(addit[i].resource->type)==1)
  {
   addit[i].rdata = (unsigned char*)malloc(ntohs(addit[i].resource->data_len));
   for(j=0;j<ntohs(addit[i].resource->data_len);j++)
   addit[i].rdata[j]=reader[j];

addit[i].rdata[ntohs(addit[i].resource->data_len)]='\0';
   reader+=ntohs(addit[i].resource->data_len);
  }
  else
  {
   addit[i].rdata=ReadName(reader,buf,&stop);
   reader+=stop;
  }
 }

//print answers
 printf("\nAnswer Records : %d \n" , ntohs(dns->ans_count) );
 for(i=0 ; i < ntohs(dns->ans_count) ; i++)
 {
  printf("Name : %s ",answers[i].name);

if( ntohs(answers[i].resource->type) == T_A) //IPv4 address
  {
   long *p;
   p=(long*)answers[i].rdata;
   a.sin_addr.s_addr=(*p); //working without ntohl
   printf("has IPv4 address : %s",inet_ntoa(a.sin_addr));
  }

if(ntohs(answers[i].resource->type)==5)
  {
   //Canonical name for an alias
   printf("has alias name : %s",answers[i].rdata);
  }

printf("\n");
 }

//print authorities
 printf("\nAuthoritive Records : %d \n" , ntohs(dns->auth_count) );
 for( i=0 ; i < ntohs(dns->auth_count) ; i++)
 {

printf("Name : %s ",auth[i].name);
  if(ntohs(auth[i].resource->type)==2)
  {
   printf("has nameserver : %s",auth[i].rdata);
  }
  printf("\n");
 }

//print additional resource records
 printf("\nAdditional Records : %d \n" , ntohs(dns->add_count) );
 for(i=0; i < ntohs(dns->add_count) ; i++)
 {
  printf("Name : %s ",addit[i].name);
  if(ntohs(addit[i].resource->type)==1)
  {
   long *p;
   p=(long*)addit[i].rdata;
   a.sin_addr.s_addr=(*p);
   printf("has IPv4 address : %s",inet_ntoa(a.sin_addr));
  }
  printf("\n");
 }
 return;
}

/*
 *
 * */
u_char* ReadName(unsigned char* reader,unsigned char* buffer,int* count)
{
 unsigned char *name;
 unsigned int p=0,jumped=0,offset;
 int i , j;

*count = 1;
 name = (unsigned char*)malloc(256);

name[0]='\0';

//read the names in 3www6google3com format
 while(*reader!=0)
 {
  if(*reader>=192)
  {
   offset = (*reader)*256 + *(reader+1) - 49152; //49152 = 11000000 00000000 ;)
   reader = buffer + offset - 1;
   jumped = 1; //we have jumped to another location so counting wont go up!
  }
  else
  {
   name[p++]=*reader;
  }

reader = reader+1;

if(jumped==0)
  {
   *count = *count + 1; //if we havent jumped to another location then we can count up
  }
 }

name[p]='\0'; //string complete
 if(jumped==1)
 {
  *count = *count + 1; //number of steps we actually moved forward in the packet
 }

//now convert 3www6google3com0 to www.google.com
 for(i=0;i<(int)strlen((const char*)name);i++)
 {
  p=name[i];
  for(j=0;j<(int)p;j++)
  {
   name[i]=name[i+1];
   i=i+1;
  }
  name[i]='.';
 }
 name[i-1]='\0'; //remove the last dot
 return name;
}

/*
 * Get the DNS servers from /etc/resolv.conf file on Linux
 * */
void get_dns_servers()
{
 FILE *fp;
 char line[200] , *p;
 if((fp = fopen("/etc/resolv.conf" , "r")) == NULL)
 {
  printf("Failed opening /etc/resolv.conf file \n");
 }

while(fgets(line , 200 , fp))
 {
  if(line[0] == '#')
  {
   continue;
  }
  if(strncmp(line , "nameserver" , 10) == 0)
  {
   p = strtok(line , " ");
   p = strtok(NULL , " ");

//p now is the dns ip :)
   //????
  }
 }

strcpy(dns_servers[0] , "208.67.222.222");
 strcpy(dns_servers[1] , "208.67.220.220");
}

/*
 * This will convert www.google.com to 3www6google3com
 * got it :)
 * */
void ChangetoDnsNameFormat(unsigned char* dns,unsigned char* host)
{
 int lock = 0 , i;
 strcat((char*)host,".");

for(i = 0 ; i < strlen((char*)host) ; i++)
 {
  if(host[i]=='.')
  {
   *dns++ = i-lock;
   for(;lock<i;lock++)
   {
    *dns++=host[lock];
   }
   lock++; //or lock=i+1;
  }
 }
 *dns++='\0';
}

(0)

相关推荐

  • linux c 获得当前进程的进程名和执行路径(示例)

    复制代码 代码如下: [sam@hzhsan test]$ more test_processname.cpp #include <limits.h>#include <stdio.h>#include <string.h>#include <unistd.h> size_t get_executable_path( char* processdir,char* processname, size_t len){        char* path_end;

  • 如何编写Linux设备驱动程序

    Linux是Unix操作系统的一种变种,在Linux下编写驱动程序的原理和思想完全类似于其他的Unix系统,但它dos或window环境下的驱动程序有很大的区别.在Linux环境下设计驱动程序,思想简洁,操作方便,功能也很强大,但是支持函数少,只能依赖kernel中的函数,有些常用的操作要自己来编写,而且调试也不方便.本人这几周来为实验室自行研制的一块多媒体卡编制了驱动程序,获得了一些经验,愿与Linux fans共享,有不当之处,请予指正. 以下的一些文字主要来源于khg,johnsonm的W

  • linux网络编程用到的网络函数详解用和使用示例

    一.概念介绍网络程序分为服务端程序和客户端程序.服务端即提供服务的一方,客户端为请求服务的一方.但实际情况是有些程序的客户端.服务器端角色不是这么明显,即互为客户端和服务端.我们编写网络程序时,一般是基于TCP协议或者UDP协议进行网络通信的.TCP:(Transfer Control Protocol)传输控制协议是一种面向连接的协议, 当我们的网络程序使用这个协议的时候,网络可以保证我们的客户端和服务端之间的传输是可靠的.UDP:(User Datagram Protocol)用户数据报协议

  • linux c程序中获取shell脚本输出的实现方法

    1. 前言Unix界有一句名言:"一行shell脚本胜过万行C程序",虽然这句话有些夸张,但不可否认的是,借助脚本确实能够极大的简化一些编程工作.比如实现一个ping程序来测试网络的连通性,实现ping函数需要写上200~300行代码,为什么不能直接调用系统的ping命令呢?通常在程序中通过 system函数来调用shell命令.但是,system函数仅返回命令是否执行成功,而我们可能需要获得shell命令在控制台上输出的结果.例如,执行外部命令ping后,如果执行失败,我们希望得到p

  • linux下实现的2048游戏示例分享

    my2048.c 复制代码 代码如下: #include"my_getch.h"#include"math.h"#include"time.h" #define SPACE() printf("    ")#define RED_NUM(n) printf("\033[;31m%4d",(n))#define GREEN_NUM(n) printf("\033[;32m%4d",(n))

  • 编写Linux实用程序的艺术

    Linux 和其他类 UNIX 系统总是附带了大量的工具,它们执行从显而易见的到不可思议的广泛功能.类 UNIX 编程环境的成功很大程度上归功于工具的高品质和选择,以及这些工具之间相互衔接的简易性. 作为开发人员,您可能会发现现有实用程序并不总是能够解决问题.虽然能够通过结合使用现有实用程序来容易地解决许多问题,然而解决其他问题却至少需要一些实 际的编程工作.这些后面的任务通常是创建新实用程序的候选任务,结合现有实用程序来创建新实用程序可以通过做最少的工作来解决问题.本文考察优秀实用程序所具有的

  • Linux/window下怎样查看某个端口被哪个程序/进程占用

    Windows: C:/Users/ewanbao>netstat -aon|findstr "123" TCP 127.0.0.1:55123 0.0.0.0:0 LISTENING 5092 TCP 127.0.0.1:55123 127.0.0.1:55124 ESTABLISHED 5092 TCP 127.0.0.1:55124 127.0.0.1:55123 ESTABLISHED 5092 UDP 0.0.0.0:123 *:* 1416 UDP [::]:123

  • linux下通过脚本实现自动重启程序

    无论什么程序都不可能完美无缺,理论上,任何程序都有Core Dump的一天,正式运营的程序,尤其是服务器程序,一旦Core Dump,后果不堪设想,有过服务器开发经验的朋友,一定都经历过深夜美梦中,被电话惊醒的惨痛经历,手忙脚乱把服务器重新启动,第二天上班还要被老板一顿狠批.所以,程序发生错误时自动重启变得很重要.这里集中讨论linux实现自动重启程序的方法. linux下实现程序的自动重启有很多方法,这里我们介绍的是通过自己写脚本来实现, 自动重启脚本 假定需要实现重启的程序名为 test ,

  • linux下非阻塞模式网络通讯模型示例分享

    复制代码 代码如下: #include <stdio.h>#include <string.h>#include <unistd.h>#include <errno.h>#include <unistd.h>#include <stdlib.h>#include <sysexits.h>#include <time.h>#include <sys/time.h>#include <sys/ty

  • Linux网络编程之socket文件传输示例

    本文所述示例程序是基于Linux平台的socket网络编程,实现文件传输功能.该示例是基于TCP流协议实现的socket网络文件传输程序.采用C语言编写.最终能够实现传输任何格式文件的文件传输程序. 具体实现代码如下: Server端代码如下: /************************************************************************* > File Name: Server.c > Author: SongLee ***********

  • Perl实现的Linux下socket代理服务器

    大家提供了许多linux开代理的方法,一般用到python等语言,一些服务器可能不会安装,然而perl可以说是linux标配的语言,给大家一款Perl语言的socket代理,代码非常少,而且还支持密码,效果还是不错,感觉很稳定. #!/usr/bin/perl $auth_enabled = 0; $auth_login = "hidden"; $auth_pass = "hidden"; $port = 44269; use IO::Socket::INET; $

随机推荐