C++实现LeetCode(106.由中序和后序遍历建立二叉树)

[LeetCode] 103. Binary Tree Zigzag Level Order Traversal 二叉树的之字形层序遍历 Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example

[LeetCode] 108.Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in wh

[LeetCode] 100. Same Tree 判断相同树 Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input:     1     

[LeetCode] 104. Maximum Depth of Binary Tree 二叉树的最大深度 Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no child

[LeetCode] 145. Binary Tree Postorder Traversal 二叉树的后序遍历 Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3},    1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could you d

[LeetCode] 102. Binary Tree Level Order Traversal 二叉树层序遍历 Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree {3,9,20,#,#,15,7},     3 / \ 9  20 /  \ 15 

[LeetCode] 99. Recover Binary Search Tree 复原二叉搜索树 Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Example 1: Input: [1,3,null,null,2]    1 / 3 \ 2 Output: [3,1,null,null,2]    3 / 1

[LeetCode] 101.Symmetric Tree 判断对称树 Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric:     1 / \ 2   2 / \   / \ 3  4 4  3 But the following is not:     1 / \ 2  

[LeetCode] 106. Construct Binary Tree from Inorder and Postorder Traversal 由中序和后序遍历建立二叉树 Given inorder and postorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given ino

[LeetCode] 105. Construct Binary Tree from Preorder and Inorder Traversal 由先序和中序遍历建立二叉树 Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given preor

[LeetCode] 889. Construct Binary Tree from Preorder and Postorder Traversal 由先序和后序遍历建立二叉树 Return any binary tree that matches the given preorder and postorder traversals. Values in the traversals pre and post are distinct positive integers. Example 1

本文实例讲述了JavaScript实现二叉树的先序.中序及后序遍历方法.分享给大家供大家参考,具体如下: 之前学数据结构的时候,学了二叉树的先序.中序.后序遍历的方法,并用C语言实现了,下文是用js实现二叉树的3种遍历,并以动画的形式展现出遍历的过程. 整个遍历过程还是采用递归的思想,原理很粗暴也很简单 先序遍历的函数: function preOrder(node){ if(!(node==null)){ divList.push(node); preOrder(node.firstEleme

本文实例讲述了Python实现树的先序.中序.后序排序算法.分享给大家供大家参考,具体如下: #encoding=utf-8 class Tree(): def __init__(self,leftjd=0,rightjd=0,data=0): self.leftjd = leftjd self.rightjd = rightjd self.data = data class Btree(): def __init__(self,base=0): self.base = base #前序遍历 根

本文实例讲述了PHP基于非递归算法实现先序.中序及后序遍历二叉树操作.分享给大家供大家参考,具体如下: 概述: 二叉树遍历原理如下: 针对上图所示二叉树遍历: 1. 前序遍历:先遍历根结点,然后遍历左子树,最后遍历右子树. ABDHECFG 2.中序遍历:先遍历左子树,然后遍历根结点,最后遍历右子树. HDBEAFCG 3.后序遍历:先遍历左子树,然后遍历右子树,最后遍历根节点. HDEBFGCA 实现方法: 先序遍历:利用栈先进后出的特性,先访问根节点,再把右子树压入,再压入左子树.这样取出的

本文实例讲述了Java二叉搜索树遍历操作.分享给大家供大家参考,具体如下: 前言:在上一节Java二叉搜索树基础中,我们对树及其相关知识做了了解,对二叉搜索树做了基本的实现,下面我们继续完善我们的二叉搜索树. 对于二叉树,有深度遍历和广度遍历,深度遍历有前序.中序以及后序三种遍历方法,广度遍历即我们寻常所说的层次遍历,如图: 因为树的定义本身就是递归定义,所以对于前序.中序以及后序这三种遍历我们使用递归的方法实现,而对于广度优先遍历需要选择其他数据结构实现,本例中我们使用队列来实现广度优先遍历.