Python学习之12个常用基础语法详解
目录
- 前言
- 1.多个字符串组合为一个字符串
- 2.字符串拆分为子字符串列表
- 3.统计列表中元素的次数
- 4.使用try-except-else-block模块
- 5.使用枚举函数得到key/value对
- 6.检查对象的内存使用情况
- 7.合并字典
- 8.计算执行一段代码所花费的时间
- 9.列表展开
- 10.列表采样
- 11.数字化
- 12.检查列表元素的唯一性
前言
前几天写了一篇关于python高级语法的文章:python进阶从青铜到王者一定会用上的Python技巧。
有读者私信说:怎么看自己是不是入门python了呢? 开发中高频python基础语法有哪些呢?
下面通过12个小案例,包含了日常开发中非常实用的语法,大家一起来检验下你会几个呢?
1. 多个字符串组合为一个字符串
list_of_strings = ['My', 'name', 'is', 'Dragon'] # Using join with the comma separator print(' '.join(list_of_strings)) # Output # My name is Dragon
2. 字符串拆分为子字符串列表
string_1 = "My name is Dragon" string_2 = "sample/ string 2" # default separator ' ' print(string_1.split()) # ['My', 'name', 'is', 'Dragon'] # defining separator as '/' print(string_2.split('/')) # ['sample', ' string 2']
3. 统计列表中元素的次数
# finding frequency of each element in a list from collections import Counter my_list = ['a','a','b','b','b','c','d','d','d','d','d'] count = Counter(my_list) # defining a counter object print(count) # Of all elements # Counter({'d': 5, 'b': 3, 'a': 2, 'c': 1}) print(count['b']) # of individual element # 3 print(count.most_common(1)) # most frequent element # [('d', 5)]
4. 使用try-except-else-block模块
a, b = 1,0 try: print(a/b) # exception raised when b is 0 except ZeroDivisionError: print("division by zero") else: print("no exceptions raised") finally: print("Run this always") # output # division by zero # Run this always
5. 使用枚举函数得到key/value对
my_list = ['a', 'b', 'c', 'd', 'e'] for index, value in enumerate(my_list): print('{0}: {1}'.format(index, value)) # 0: a # 1: b # 2: c # 3: d # 4: e
6. 检查对象的内存使用情况
import sys num = 21 print(sys.getsizeof(num)) # In Python 3, 28
7. 合并字典
dict_1 = {'apple': 9, 'banana': 6} dict_2 = {'banana': 4, 'orange': 8} combined_dict = {**dict_1, **dict_2} print(combined_dict) # Output # {'apple': 9, 'banana': 4, 'orange': 8}
8. 计算执行一段代码所花费的时间
import time start_time = time.time() # Code to check follows for i in range(10**5): a, b = 1,2 c = a+ b # Code to check ends end_time = time.time() time_taken_in_micro = (end_time- start_time)*(10**6) print(time_taken_in_micro) # output # 28770.217895507812
9. 列表展开
from iteration_utilities import deepflatten # if you only have one depth nested_list, use this def flatten(l): return [item for sublist in l for item in sublist] l = [[1,2,3],[3]] print(flatten(l)) # [1, 2, 3, 3] # if you don't know how deep the list is nested l = [[1,2,3],[4,[5],[6,7]],[8,[9,[10]]]] print(list(deepflatten(l, depth=3))) # [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
10. 列表采样
import random my_list = ['a', 'b', 'c', 'd', 'e'] num_samples = 2 samples = random.sample(my_list,num_samples) print(samples) # [ 'a', 'e'] this will have any 2 random values
11. 数字化
num = 123456 # using map list_of_digits = list(map(int, str(num))) print(list_of_digits) # [1, 2, 3, 4, 5, 6] # using list comprehension list_of_digits = [int(x) for x in str(num)] print(list_of_digits) # [1, 2, 3, 4, 5, 6]
12. 检查列表元素的唯一性
def unique(l): if len(l)==len(set(l)): print("All elements are unique") else: print("List has duplicates") unique([1,2,3,4]) # All elements are unique unique([1,1,2,3]) # List has duplicates
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