C++基于递归和非递归算法求二叉树镜像的方法
本文实例讲述了C++基于递归和非递归算法求二叉树镜像的方法。分享给大家供大家参考,具体如下:
/*求二叉树镜像 -- 采用递归和非递归方法 经调试可运行源码及分析如下: ***/ #include <stdlib.h> #include <iostream> #include <queue> using std::cout; using std::cin; using std::endl; using std::queue; /*二叉树结点定义*/ typedef struct BTreeNode { char elem; struct BTreeNode *pleft; struct BTreeNode *pright; }BTreeNode; /* 求二叉树镜像 递归方式步骤: 如果proot为NULL,则为空树,返回; 如果proot不为NULL,交换proot左右结点,然后分别求左右子树的镜像; */ /*递归求二叉树镜像*/ void get_bitree_mirror(BTreeNode* proot) { if (proot == NULL) return ; BTreeNode* temp_node = proot->pleft; proot->pleft = proot->pright; proot->pright = temp_node; get_bitree_mirror(proot->pleft); get_bitree_mirror(proot->pright); return ; } /* 非递归方式步骤如下: 借助队列 首先,将根节点proot入队; 第一步:当队列非空时,获取当前层次的节点总数,即当前队列的长度;执行第二步; 第二步:按照当前层的节点总数,出队进行遍历节点,在遍历时, 交换左右节点,如果左右节点存在,则入队; 当遍历完当前层所有节点时,遍历下一层,执行第一步。 */ void get_bitree_mirror_leveltraverse(BTreeNode* proot) { if(proot == NULL) return ; queue <BTreeNode*> que; que.push(proot); int level_nodes_number = 0; while (!que.empty())//层次遍历 { level_nodes_number = que.size(); int level_count = 0; while (level_count < level_nodes_number) { ++level_count; proot = que.front(); que.pop(); //交换左右子节点 BTreeNode* temp_node = proot->pleft; proot->pleft = proot->pright; proot->pright = temp_node; if(proot->pleft != NULL) que.push(proot->pleft); if(proot->pright != NULL) que.push(proot->pright); } } return ; } /*初始化二叉树根节点*/ BTreeNode* btree_init(BTreeNode* &bt) { bt = NULL; return bt; } /*先序创建二叉树*/ void pre_crt_tree(BTreeNode* &bt) { char ch; cin >> ch; if (ch == '#') { bt = NULL; } else { bt = new BTreeNode; bt->elem = ch; pre_crt_tree(bt->pleft); pre_crt_tree(bt->pright); } } /*先序遍历*/ void pre_order_traverse(BTreeNode* proot) { if(proot == NULL) return; cout<< proot->elem << " "; pre_order_traverse(proot->pleft); pre_order_traverse(proot->pright); return; } int main() { int tree_node_number = 0; BTreeNode *bt; btree_init(bt);//初始化根节点 pre_crt_tree(bt);//创建二叉树 cout << "先序遍历输出如下:" << endl; cout << "调用镜像函数前:" << endl; pre_order_traverse(bt); cout << endl; get_bitree_mirror(bt); cout << "递归调用镜像函数后:" << endl; pre_order_traverse(bt); cout << endl; cout << "非递归调用镜像函数后:" << endl; get_bitree_mirror_leveltraverse(bt); pre_order_traverse(bt); cout << endl; system("pause"); return 0; }
/* 运行结果: a b c # # # d e # # # ------以上为输入----------- ------以下为输出----------- 先序遍历输出如下: 调用镜像函数前: a b c d e 递归调用镜像函数后: a d e b c 非递归调用镜像函数后: a b c d e 请按任意键继续. . . --------------------------------- 本例创建的二叉树形状: a b d c e 调用递归求二叉树镜像形状: a d b e c 再次调用非递归求二叉树镜像形状(即镜像的镜像): a b d c e */
希望本文所述对大家C++程序设计有所帮助。
赞 (0)