vector, list, map在遍历时删除符合条件的元素实现方法
直接看源码,内有详细解释
/* 测试vector, list, map遍历时删除符合条件的元素 本代码测试环境: ubuntu12 + win7_x64 */ #include <iostream> #include <vector> #include <list> #include <map> #include <iterator> using namespace std; void Remove1(vector<int> &vec, int num) { for (vector<int>::iterator it = vec.begin(); it != vec.end();) { if (*it == num) it = vec.erase(it); else it++; } } void Remove2(list<int> &lst, int num) { list<int>::iterator it; for (it=lst.begin(); it!=lst.end();) { if (*it == num) { lst.erase(it++); } else it++; } } void initMap(map<int, int>& m, int arr[], int arrLen) { for(int i = 0; i < arrLen; i++) m[i] = arr[i]; } void Remove_map(map<int, int>& m, int num) { map<int, int>::iterator it; for(it = m.begin(); it != m.end();) { if (it->second == num) m.erase(it++); else it++; } } void displayMap(map<int, int>& m) { map<int, int>::iterator it = m.begin(); while(it != m.end()) { cout << "key = " << it->first << ", value = " << it->second << endl; it++; } cout << endl; } int main(void) { int arr[] = {1, 3, 5, 5, 5, 13, 7, 5, 7, 9}; int arrLen = sizeof(arr) / sizeof(arr[0]); #if 1 // test vector vector<int> vec(arr, arr+arrLen); Remove1(vec, 5); copy(vec.begin(), vec.end(), ostream_iterator<int>(cout, " ")); cout << endl << endl; #endif // test list list<int> lst(arr, arr+arrLen); Remove2(lst, 5); copy(lst.begin(), lst.end(), ostream_iterator<int>(cout, " ")); cout << endl << endl; // test map map<int, int> m; initMap(m, arr, arrLen); Remove_map(m, 5); displayMap(m); return 0; } /* Win7_x64运行结果: 1 3 13 7 7 9 1 3 13 7 7 9 key = 0, value = 1 key = 1, value = 3 key = 5, value = 13 key = 6, value = 7 key = 8, value = 7 key = 9, value = 9 Ubuntu12运行结果: [zcm@cpp #54]$make g++ -Wall -Os -DLINUX -o a a.cpp [zcm@cpp #55]$./a 1 3 13 7 7 9 1 3 13 7 7 9 key = 0, value = 1 key = 1, value = 3 key = 5, value = 13 key = 6, value = 7 key = 8, value = 7 key = 9, value = 9 */
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