基于Python计算圆周率pi代码实例
一 计算公式:
二 实现代码
(1)
import math from tqdm import tqdm import time total,s,n,t=0.0,1,1.0,1.0 while(math.fabs(t)>=1e-6): total+=t n+=2 s=-s t=s/n k=total*4 print("π值是{:.10f} 运行时间为{:.4f}秒".format(k,time.clock())) for i in tqdm(range(101)): print("\r{:3}%".format(i),end="") time.sleep(0.1)
(2)
import time import math class Index(object): def __init__(self, number=50, decimal=2): self.decimal = decimal self.number = number self.a = 100/number def __call__(self, now, total): percentage = self.percentage_number(now, total) well_num = int(percentage / self.a) progress_bar_num = self.progress_bar(well_num) result = "\r%s %s" % (progress_bar_num, percentage) return result def percentage_number(self, now, total): return round(now / total * 100, self.decimal) def progress_bar(self, num): well_num = "#" * num space_num = " " * (self.number - num) return '[%s%s]' % (well_num, space_num) index = Index() total,s,n,t=0.0,1,1.0,1.0 while(math.fabs(t)>=1e-6): total+=t n+=2 s=-s t=s/n k=total*4 start = 371 for i in range(start + 1): print(index(i, start), end='') time.sleep(0.01) print("\n π值是{:.10f}".format(k))
(3)
import time import math total,s,n,t=0.0,1,1.0,1.0 while(math.fabs(t)>=1e-6): total+=t n+=2 s=-s t=s/n k=total*4 scale=50 print("".center(scale//2,"-")) start = time.perf_counter() for i in range(scale+1): a="*"*i b="."*(scale-i) c=(i/scale)*100 d=time.perf_counter() - start print("\r{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,d),end='') time.sleep(0.1) print("\n π值是{:.10f}".format(k))
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