oracle 函数判断字符串是否包含图片格式的实例代码
首先是写一个分割字符串的函数,返回table类型
CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2) RETURN ty_str_split IS j INT := 0; i INT := 1; len INT := 0; len1 INT := 0; str VARCHAR2 (4000); str_split ty_str_split := ty_str_split (); BEGIN len := LENGTH (p_str); len1 := LENGTH (p_delimiter); WHILE j < len LOOP j := INSTR (p_str, p_delimiter, i); IF j = 0 THEN j := len; str := SUBSTR (p_str, i); str_split.EXTEND; str_split (str_split.COUNT) := str; IF i >= len THEN EXIT; END IF; ELSE str := SUBSTR (p_str, i, j - i); i := j + len1; str_split.EXTEND; str_split (str_split.COUNT) := str; END IF; END LOOP; RETURN str_split; END fn_split;
上面这个函数可以将字符串分割返回table
create or replace function fn_ispng( strpng in varchar2 ) return number is v_num number; begin WITH t1 AS (select * from table (fn_split(strpng,'.')) ) select count(1) into v_num from t1 where t1.column_value in ('png', 'jpg','jpeg','gif','bmp','eps'); return v_num; end fn_ispng;
上面这个是判断是否是图片格式,的图片格式返回1
select fn_ispng('dfdfd.png') from dual;
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