js 模仿锚点定位的实现方法
如下所示:
<div class="designer-bg ov"> <div class="w-77 f-l designer-nav"> <ul id="scroll_nav"> <li class="designer-nav-li"><a href="" title="" data-nav="a">A - E</a></li> <li class="designer-nav-li"><a href="" title="" data-nav="f">F - L</a></li> <li class="designer-nav-li"><a href="" title="" data-nav="m">M - T</a></li> <li class="designer-nav-li"><a href="" title="" data-nav="u">U - Z</a></li> </ul> </div> <script type="text/javascript"> $(function(){ var navLinks = $('#scroll_nav').find('a') , target_ul = $('#designer_nav_name') , _top = 0; $.each(navLinks , function( i , elem ){ $(elem).attr('data-to' , i == 0 ? 0 : _top); var id = $(elem).attr('data-nav'); var _h4 = $('#'+id).parent(); _top = parseInt(_h4.next().height()) + _top + parseInt(_h4.height()); $(elem).bind('click', function(){ target_ul[0].scrollTop = $(this).attr('data-to'); return false; }); }); $('#designer_nav_name li').click(function( e ){ var designer_name_href= $(this).find('a').attr("href"); $.getJSON("test.php?action=test&jsoncallback=?&testid="+testidhref,function(data){ $('#Ttai').html(data.catwalk); }); e.preventDefault(); }); }) </script> <div class="f-r designer-index" id="designer_nav_name"> <h4><a name="a" id="a"><strong>A</strong></a></h4> <ul> <li></li> </ul> <h4><a name="f" id="f"><strong>F</strong></a></h4> <ul> <li></li> </ul><h4><a name="m" id="m"><strong>M</strong></a></h4><ul> <li></li> </ul><h4><a name="u" id="u"><strong>U</strong></a></h4><ul> <li></li> </ul> </div> </div>
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