如何在前台脚本通过json传递数据到后台(使用微软自带的ajax)
首先,我们要在前台引入json的脚本,以便于把js对象序列化
<script type="text/javascript" src="/js/jquery.json-2.4.min.js"></script>
然后我们在前台声明一个类,将你要保存的值放到类里面,最后序列化
function Save() {
var examId = '<%=ExamId %>';
var yearTerm = $("#<%=DDLYearTerm.ClientID %>").val();
var examType = $("#<%=DDLExamType.ClientID %>").val();
var examDate = $("#ExamDate").val();
var examName = $("#ExamName").val();
var exam = {};
exam["ExamId"] = examId;
exam["YearTerm"] = yearTerm;
exam["ExamType"] = examType;
exam["ExamDate"] = examDate;
exam["ExamName"] = examName;
var json = $.toJSON(exam);
var Result = AjaxController.EditExam(json).value;
if (Result == "Success")
{
alert("保存成功");
parent.$.fancybox.close();
}
else
{
alert(Result);
}
}
然后我们在后台,进行反序列化,并使用值.因为我们使用ajax所以要在后台的方法上加上[Ajax.AjaxMethod]特性,并且在你前台所在页面的cs里面也要加上Ajax的注册.具体使用看
微软 ajax 库 的使用方法( ajax.ajaxMethod) http://www.jb51.net/article/40764.htm
protected void Page_Load(object sender, EventArgs e)
{
Ajax.Utility.RegisterTypeForAjax(typeof(Youjiao.xxt.BLL.Controller.AjaxController));
if (!IsPostBack)
{
Databind();
}
}
[Ajax.AjaxMethod]
public string EditExam(string value)
{
string Result = "";
try
{
if (HttpContext.Current.Request.IsAuthenticated)
{
EditExam editExam = JsonSerializeHelper.DeserializeFromJson<EditExam>(value);
ExamController eController = new ExamController();
eController.EditExam(editExam);
Result = "Success";
}
else
{
Result = "会话无效,请重登录!";
}
}
catch (Exception ex)
{
Result = ex.Message;
}
return Result;
}
图片:
[Serializable]
public class EditExam
{
public string ExamId { get; set; }
public string YearTerm { get; set; }
public string ExamType { get; set; }
public string ExamDate { get; set; }
public string ExamName { get; set; }
}
这样就可以很好的避免在前台js里面传入大量的参数,后台也可以直接反序列化为类来点出成员的值了