Spring Boot中优雅的获取yml文件工具类

如何在spring boot中优雅的获取.yml文件工具类呢

代码如下：

package com.common.base.utils.base;
import com.common.base.generator.ResourceManager;
import org.yaml.snakeyaml.Yaml;
import java.io.InputStream;
import java.util.HashMap;
import java.util.Map;
/**
 * yml文件工具类
 */
public class YmlUtils {
  private static String bootstrap_file = "bootstrap.yml";
  private static Map<String,String> result = new HashMap<>();
  /**
   * 根据文件名获取yml的文件内容
   * @return
   */
  public static Map<String,String> getYmlByFileName(String file){
    result = new HashMap<>();
    if(file == null)
      file = bootstrap_file;
    InputStream in = ResourceManager.class.getClassLoader().getResourceAsStream(file);
    Yaml props = new Yaml();
    Object obj = props.loadAs(in,Map.class);
    Map<String,Object> param = (Map<String, Object>) obj;
    for(Map.Entry<String,Object> entry:param.entrySet()){
      String key = entry.getKey();
      Object val = entry.getValue();

      if(val instanceof Map){
        forEachYaml(key,(Map<String, Object>) val);
      }else{
        result.put(key,val.toString());
      }
    }
    return result;
  }
  /**
   * 根据key获取值
   * @param key
   * @return
   */
  public static String getValue(String key){
    Map<String,String> map = getYmlByFileName(null);
    if(map==null)return null;
    return map.get(key);
  }
  /**
   * 遍历yml文件，获取map集合
   * @param key_str
   * @param obj
   * @return
   */
  public static Map<String,String> forEachYaml(String key_str,Map<String, Object> obj){
    for(Map.Entry<String,Object> entry:obj.entrySet()){
      String key = entry.getKey();
      Object val = entry.getValue();
      String str_new = "";
      if(StringUtils.isNotNull(key_str)){
        str_new = key_str+ "."+key;
      }else{
        str_new = key;
      }
      if(val instanceof Map){
        forEachYaml(str_new,(Map<String, Object>) val);
      }else{
        result.put(str_new,val.toString());
      }
    }
    return result;
  }
  /**
   * 获取bootstrap.yml的name
   * @return
   */
  public static String getApplicationName(){
    return getYmlByFileName(bootstrap_file).get("spring.application.name");
  }
  /**
   * 获取bootstrap.yml的name
   * @return
   */
  public static String getApplicationName1(){
    String name = getYmlByFileName(bootstrap_file).get("spring.application.name");
    return name + "center";
  }
  public static void main(String[] args) {
    System.out.println(getApplicationName());
  }
}

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