java实现浮点数转人民币的小例子
import java.util.ArrayList;
import java.util.List;
public class RMBConverter2 implements IRMBConverter {
private static final String [] RMB_NUMBER ={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
private static final String [] RMB_ATTR = {"元","十","佰","仟","万","十","百","仟","亿","十","佰","仟","万","十","佰","仟"};
private static final String[] RMB_FEN = {"分","角"};
@Override
public String change2RMB(double counts) {
StringBuffer rsBuf = new StringBuffer();
if (counts == 0L) {
return "零";
}
if (counts < 0)
rsBuf.append("负");
String zheng = strConverse(String.valueOf((long)counts));
String xiao = strConverse(String.valueOf(Math.round((counts - (long)counts)*100)));
char [] zhengArray = zheng.toCharArray();
char [] xiaoArray = xiao.toCharArray();
int zLength = zhengArray.length;
int xLength = xiaoArray.length;
List<String> zhengList = new ArrayList<String>();
for(int i =0; i< zLength; i++) {
int value = Integer.parseInt(""+zhengArray[i]);
if (value == 0 && (i != 4) && (i != 8) && i != 0) {
zhengList.add(RMB_NUMBER[value]);
}else {
zhengList.add(RMB_NUMBER[value]+
RMB_ATTR[i]);
}
}
for(int i = zhengList.size()-1; i>=0; i--) {
rsBuf.append(zhengList.get(i));
}
for(int i =0; i<xLength ;i++) {
int value = Integer.parseInt(""+xiaoArray[i]);
if (value > 0 ) {
rsBuf.append(RMB_NUMBER[value])
.append(RMB_FEN[xLength-i-1]);
}
}
String rs = rsBuf.toString();
rs = rs.replaceAll("零+", "零");
rs = rs.replaceAll("零元", "元");
rs = rs.replaceAll("零万", "万");
rs = rs.replaceAll("零亿", "亿");
rs = rs.replaceAll("亿万", "亿");
return rs;
}
private String strConverse(String str) {
StringBuffer rs = new StringBuffer();
char [] strArray = str.toCharArray();
for(int i = str.length()-1; i>=0; i--) {
rs.append(strArray[i]);
}
return rs.toString();
}
public static void main(String args []) {
RMBConverter2 c2 = new RMBConverter2();
System.out.println(c2.change2RMB(2001004.10));
System.out.println(c2.change2RMB(2000000.10));
System.out.println(c2.change2RMB(0L));
System.out.println(c2.change2RMB(1121000010000000L));
}
}