python实现简单井字棋游戏

井字棋，英文名叫Tic-Tac-Toe，是一种在3*3格子上进行的连珠游戏，和五子棋类似，由于棋盘一般不画边框，格线排成井字故得名。游戏需要的工具仅为纸和笔，然后由分别代表O和X的两个游戏者轮流在格子里留下标记（一般来说先手者为X），任意三个标记形成一条直线，则为获胜。

游戏的难点在于，如何判断连接成了一条线；横、竖、斜三个方向；

游戏的代码：

#!/usr/bin/env python3
# -*- coding:utf-8 -*-
u'''
Created on 2019年4月13日

@author: wuluo
'''
__author__ = 'wuluo'
__version__ = '1.0.0'
__company__ = u'重庆交大'
__updated__ = '2019-04-13'

# 创建井字棋的程序
def initBoard():
   global board # 调用全局的board
   board = [None] * 3
   print("井字棋：")
   for i in range(len(board)):
      board[i] = ["+ "] * 3

# 打印井字棋的程序
def printBoard():
   global board
   for i in range(len(board)):
      for j in range(len(board[i])):
         print(board[i][j], end=" ")
      print("")

# 开始下棋的程序
def startGame():
   global board
   player = 0
   while isGameContinue():
      if player <= 8:
         if player % 2 == 0:
            # 甲方下棋
            print("==>黑方下棋")
            if not playChess("x"):
               continue
         else:
            # 乙方下棋
            print("==>白方下棋")
            if not playChess("○"):
               continue
         player += 1
      else:
         print("平局")
         break

def playChess(chess):
   # 获取位置
   x = int(input("==> X=")) - 1
   y = int(input("==> Y=")) - 1
   if board[x][y] == "+ ":
      board[x][y] = chess
      printBoard()
      return True # 落子成功
   else:
      print("==> 已有棋子 请重新落子\a")
      printBoard()
      return False # 落子失败

def isGameContinue():
   for i in range(len(board)):
      for j in range(len(board[i])):
         if board[i][j] != "+ ":
            # 横向
            if j == 0:
               if board[i][j] == board[i][j + 1] == board[i][j + 2]:
                  whoWin(i, j)
                  return False
            # 竖向
            if i == 0:
               if board[i][j] == board[i + 1][j] == board[i + 2][j]:
                  whoWin(i, j)
                  return False
            # 正斜
            if i == 0 and j == 0:
               if board[i][j] == board[i + 1][j + 1] == board[i + 2][j + 2]:
                  whoWin(i, j)
                  return False
            # 反斜
            if i == 2 and j == 0:
               if board[i][j] == board[i - 1][j + 1] == board[i - 2][j + 2]:
                  whoWin(i, j)
                  return False
   return True

def whoWin(i, j):
   if board[i][j] == "x":
      print("黑方胜！")
   else:
      print("白方胜！")
   for i in range(3):
      print("win")

class main():
   board = []
   initBoard()
   printBoard()
   startGame()

if __name__ == "__main__":
   main()

游戏结果：

还有一种结果是平局：

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