c读取一行字符串,以及c++读取一行字符串的实例
一 c读取一行字符串
1 gets
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
int size = 1024;
char* buff = (char*)malloc(size);
// read lines
while(NULL != gets(buff)){
printf("Read line with len: %d\n", strlen(buff));
printf("%s", buff);
}
// free buff
free(buff);
}
利用getchar()读取一个个字符来读取一行
#include <stdio.h>
#include <stdlib.h>
int my_getline(char* line, int max_size)
{
int c;
int len = 0;
while( (c = getchar()) != EOF && len < max_size ){
line[len++] = c;
if('\n' == c)
break;
}
line[len] = '\0';
return len;
}
int main()
{
int max_size = 1024;
char* buff = (char*)malloc( sizeof(char) * max_size );
//getline
int len;
while(0 != (len = my_getline(buff, max_size))){
printf("Read line with len: %d\n", len);
printf("%s", buff);
}
free(buff);
}
二 c++读取一行字符串
cin.get()和cin.getline()
#include<iostream>
using namespace std;
int main()
{
cout << "----------getline忽略'\\n-----------------" << endl;
char str0[30], str1[30];
cin.getline(str0, 30);
cin.getline(str1, 30);
cout << "str0:" << str0 << endl;
cout << "str1:" << str1 << endl;
cout << "---------利用get()消除get()遗留下来的'\\n'-------" << endl;
char str2[30], str3[30];
cin.get(str2, 30).get(); // 注意这里！
cin.get(str3, 30).get();
cout << "str1: " << str2 << endl;
cout << "str2: " << str3 << endl;
cout << "--------没消除get()遗留下来的'\\n'就被下一个get()读取了，所以str5输出为空-----" << endl;
char str4[30], str5[30];
cin.get(str4, 30); // 注意这里！
cin.get(str5, 30);
cout << "str4: " << str4 << endl;
cout << "str5: " << str5 << endl;
return 0;
}
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