基于C语言实现简单的扫雷小游戏

本文实例为大家分享了C语言实现简单的扫雷小游戏的具体代码，供大家参考，具体内容如下

首先来规划一下扫雷游戏实现的几个步骤：

初始化棋盘：二维数组的遍历及赋值
为了后续代码的简洁方便，我们用'0'来初始化

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < rows; i++)
 {
  for (j = 0; j < cols; j++)
  {
   board[i][j] = set;
  }
 }
}

布置雷的信息：应用随机函数进行赋值

void SetMine(char mine[ROWS][COLS], int row, int col)
{
 int count = EASY_COUNT;
 while (count)
 {
  int x = rand() % row + 1;
  int y = rand() % col + 1;

  if (mine[x][y] == '0')
  {
   mine[x][y] = '1';
   count--;
  }
 }
}

排查雷：

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
 int x = 0;
 int y = 0;
 int win = 0;
 while (win<row*col- EASY_COUNT)
 {
  printf("请输入要排查的坐标->");
  scanf("%d %d", &x, &y);
  if (x >= 1 && x <= row && y >= 1 && y <= col)
  {
   if (mine[x][y] == '1')
   {
    printf("很遗憾你被炸死了\n");
    DisplayBoard(mine, row, col);
    break;
   }
   else
   {
    //计算x,y坐标周围有几个雷
    int n=get_mine_count(mine, x, y);
    show[x][y] = n + '0';
    DisplayBoard(show, row, col);
    win++;

   }

  }
  else
   printf("输入坐标错误，请重新输入\n");

 }
 if (win == row * col - EASY_COUNT)
 {
  printf("恭喜你，排雷成功\n");
  DisplayBoard(mine, row, col);
 }
}

下面是游戏实现的完整代码，依旧是分为了3个版块，为了更好的管理代码，提高代码的可读性和可移植性

game2.h

#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#define ROW 9
#define COL 9
#define  EASY_COUNT 10

#define ROWS ROW+2
#define COLS COL+2

//初始化棋盘
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
//打印棋盘
void DisplayBoard(char board[ROWS][COLS], int row, int col);
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col);
//排查雷
void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col);

game2.c

#include "game2.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
 int i = 0;
 int j = 0;
 for (i = 0; i < rows; i++)
 {
  for (j = 0; j < cols; j++)
  {
   board[i][j] = set;
  }
 }
}
void DisplayBoard(char board[ROWS][COLS], int row, int col)
{
 int i = 0;
 int j = 0;
 for (i = 0; i <= col; i++)
 {
  printf("%d ", i);
 }
 printf("\n");
 for (i = 1; i <= row; i++)
 {
  printf("%d ", i);
  for (j = 1; j <= col; j++)
  {
   printf("%c ", board[i][j]);
  }
  printf("\n");

 }
}
//布置雷
void SetMine(char mine[ROWS][COLS], int row, int col)
{
 int count = EASY_COUNT;
 while (count)
 {
  int x = rand() % row + 1;
  int y = rand() % col + 1;

  if (mine[x][y] == '0')
  {
   mine[x][y] = '1';
   count--;
  }
 }
}
static int get_mine_count(char mine[ROWS][COLS], int x, int y)
{
 return mine[x - 1][y] +
  mine[x - 1][y - 1] +
  mine[x][y - 1] +
  mine[x + 1][y] +
  mine[x + 1][y + 1] +
  mine[x][y + 1] +
  mine[x - 1][y + 1]+
  mine[x+1][y-1]-8*'0';
}

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
 int x = 0;
 int y = 0;
 int win = 0;
 while (win<row*col- EASY_COUNT)
 {
  printf("请输入要排查的坐标->");
  scanf("%d %d", &x, &y);
  if (x >= 1 && x <= row && y >= 1 && y <= col)
  {
   if (mine[x][y] == '1')
   {
    printf("很遗憾你被炸死了\n");
    DisplayBoard(mine, row, col);
    break;
   }
   else
   {
    //计算x,y坐标周围有几个雷
    int n=get_mine_count(mine, x, y);
    show[x][y] = n + '0';
    DisplayBoard(show, row, col);
    win++;

   }

  }
  else
   printf("输入坐标错误，请重新输入\n");

 }
 if (win == row * col - EASY_COUNT)
 {
  printf("恭喜你，排雷成功\n");
  DisplayBoard(mine, row, col);
 }
}

test.c

#include "game2.h"
void menu()
{
 printf("**************************\n");
 printf("*******   1.play   *******\n");
 printf("*******   0.exit   *******\n");
 printf("**************************\n");

}

void game()
{
 //创建数组
 char mine[ROWS][COLS] = { 0 };//存放布置好的雷的信息
 char show[ROWS][COLS] = { 0 };//存放排查出的雷的信息

 //初始化mine数组全部为‘0'
 InitBoard(mine, ROWS, COLS, '0');
 //初始化show数组全部为‘0'
 InitBoard(show, ROWS, COLS, '*');

 //打印棋盘
 //DisplayBoard(mine, ROW, COL);

 //布置雷
 SetMine(mine, ROW, COL);
 DisplayBoard(show, ROW, COL);

 //DisplayBoard(mine, ROW, COL);

 //排查雷
 FindMine(mine, show, ROW, COL);
}
void test()
{
 int input = 0;
 srand((unsigned int)time(NULL));
 do
 {
  menu();
  printf("请选择->");
  scanf("%d", &input);
  switch (input)
  {
  case 1:
   game();
   break;

  case 0:
   printf("退出游戏\n");
   break;

  default:
   printf("选择错误\n");
   break;
  }
 } while (input);
}
int main()
{
 test();
 return 0;

}

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