python 如何获取页面所有a标签下href的值
看代码吧~
# -*- coding:utf-8 -*- #python 2.7 #http://tieba.baidu.com/p/2460150866 #标签操作 from bs4 import BeautifulSoup import urllib.request import re #如果是网址,可以用这个办法来读取网页 #html_doc = "http://tieba.baidu.com/p/2460150866" #req = urllib.request.Request(html_doc) #webpage = urllib.request.urlopen(req) #html = webpage.read() html=""" <html><head><title>The Dormouse's story</title></head> <body> <p class="title" name="dromouse"><b>The Dormouse's story</b></p> <p class="story">Once upon a time there were three little sisters; and their names were <a href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" class="sister" id="xiaodeng"><!-- Elsie --></a>, <a href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" class="sister" id="link2">Lacie</a> and <a href="http://example.com/tillie" rel="external nofollow" class="sister" id="link3">Tillie</a>; <a href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" class="sister" id="xiaodeng">Lacie</a> and they lived at the bottom of a well.</p> <p class="story">...</p> """ soup = BeautifulSoup(html, 'html.parser') #文档对象 #查找a标签,只会查找出一个a标签 #print(soup.a)#<a class="sister" href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" id="xiaodeng"><!-- Elsie --></a> for k in soup.find_all('a'): print(k) print(k['class'])#查a标签的class属性 print(k['id'])#查a标签的id值 print(k['href'])#查a标签的href值 print(k.string)#查a标签的string
如果,标签<a>中含有其他标签,比如<em>..</em>,此时要提取<a>中的数据,需要用k.get_text()
soup = BeautifulSoup(html, 'html.parser') #文档对象 #查找a标签,只会查找出一个a标签 for k in soup.find_all('a'): print(k) print(k['class'])#查a标签的class属性 print(k['id'])#查a标签的id值 print(k['href'])#查a标签的href值 print(k.string)#查a标签的string
如果,标签<a>中含有其他标签,比如<em>..</em>,此时要提取<a>中的数据,需要用k.get_text()
通常我们使用下面这种模式也是能够处理的,下面的方法使用了get()。
html = urlopen(url) soup = BeautifulSoup(html, 'html.parser') t1 = soup.find_all('a') print t1 href_list = [] for t2 in t1: t3 = t2.get('href') href_list.append(t3)
补充:python爬虫获取任意页面的标签和属性(包括获取a标签的href属性)
看代码吧~
# coding=utf-8 from bs4 import BeautifulSoup import requests # 定义一个获取url页面下label标签的attr属性的函数 def getHtml(url, label, attr): response = requests.get(url) response.encoding = 'utf-8' html = response.text soup = BeautifulSoup(html, 'html.parser'); for target in soup.find_all(label): try: value = target.get(attr) except: value = '' if value: print(value) url = 'https://baidu.com/' label = 'a' attr = 'href' getHtml(url, label, attr)
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