golang等待触发事件的实例
我就废话不多说了,大家还是直接看代码吧~
type Wait interface { // Register waits returns a chan that waits on the given ID. // The chan will be triggered when Trigger is called with // the same ID. Register(id uint64) <-chan interface{} // Trigger triggers the waiting chans with the given ID. Trigger(id uint64, x interface{}) IsRegistered(id uint64) bool } type list struct { l sync.RWMutex m map[uint64]chan interface{} } func Newlist() Wait { return &list{m : make(map[uint64]chan interface{})} } //注册 func (w *list) Register(id uint64) <-chan interface{} { w.l.Lock() defer w.l.Unlock() ch := w.m[id] if ch != nil { log.Fatal("dup id error") return nil } ch = make(chan interface{},1) w.m[id] = ch return ch } //触发 func (w *list) Trigger(id uint64, x interface{}) { w.l.Lock() ch := w.m[id] delete(w.m,id) w.l.Unlock() if ch != nil { ch <- x close(ch) } } //判断该id是否被注册 func (w *list) IsRegistered(id uint64) bool { w.l.RLock() defer w.l.Unlock() _,ok := w.m[id] return ok }
示例
var timeOutDuration = time.Minute*10 func main() { list := Newlist() rid := uint64(time.Now().UnixNano()) go func() { ch := list.Register(rid) fmt.Println("start register:",rid) if ch == nil { return } select { case x := <- ch: fmt.Printf("trigger over id:%d,x:%v\n",rid,x) case <-time.After(timeOutDuration): log.Println("timeout error:",rid) } }() time.Sleep(time.Second) rid2 := uint64(time.Now().UnixNano()) go func() { ch := list.Register(rid2) fmt.Println("start register:",rid2) if ch == nil { return } select { case x := <- ch: fmt.Printf("trigger over id:%d,x:%v\n",rid2,x) case <-time.After(timeOutDuration): log.Println("timeout error:",rid2) } }() go func() { time.Sleep(time.Second*5) list.Trigger(rid,"Hello") time.Sleep(time.Second*3) list.Trigger(rid2,"World") }() select { } }
补充:GO 程序等待一段时间执行
我就废话不多说了,大家还是直接看代码吧~
package main import ( "fmt" "time" ) func main() { fmt.Println(time.Now()) //等1秒 time.Sleep(time.Second * 1) fmt.Println(time.Now()) //等1秒 <-time.After(time.Second * 1) fmt.Println(time.Now()) }
以上为个人经验,希望能给大家一个参考,也希望大家多多支持我们。如有错误或未考虑完全的地方,望不吝赐教。
赞 (0)