java中 Set与Map排序输出到Writer详解及实例
java中 Set与Map排序输出到Writer详解及实例
一般来说java.util.Set,java.util.Map输出的内容的顺序并不是按key的顺序排列的,但是java.util.TreeMap,java.util.TreeSet的实现却可以让Map/Set中元素内容以key的顺序排序,所以利用这个特性,可以将Map/Set转为TreeMap,TreeSet然后实现排序输出。
以下是实现的代码片段:
/** * 对{@link Map}中元素以key排序后,每行以{key}={value}形式输出到{@link Writer}<br> * map为空或null时则不向writer写入任何内容 * @param map * @param writer 为null抛出{@link IllegalArgumentException} * @throws IOException */ public static void storeSortedMap(Map<String,String> map,Writer writer) throws IOException { if(null==writer) throw new IllegalArgumentException("the arugment 'writer' must not be null "); TreeMap<String, String> sortedMap = new TreeMap<String,String>(); if(null!=map) sortedMap.putAll(map); BufferedWriter bw=(writer instanceof BufferedWriter)?(BufferedWriter)writer : new BufferedWriter(writer); for (Entry<String,String> e:sortedMap.entrySet()) { bw.write(e.getKey() + "=" + e.getValue()); bw.newLine(); } bw.flush(); } /** * 对 {@link Collection}中元素排序后(去除重复),元素分行输出到{@link Writer}<br> * collection为空或null时则不向writer写入任何内容 * @param collection * @param writer 为null抛出{@link IllegalArgumentException} * @throws IOException */ public static void storeSortedSet(Collection<String> collection,Writer writer) throws IOException { if(null==writer) throw new IllegalArgumentException("the arugment 'writer' must not be null "); TreeSet<String> sortedSet = new TreeSet<String>(); if(null!=collection) sortedSet.addAll(collection); BufferedWriter bw=(writer instanceof BufferedWriter)?(BufferedWriter)writer : new BufferedWriter(writer); for (String e:sortedSet) { bw.write(e); bw.newLine(); } bw.flush(); }
调用示例如下:
Map<String,String> map; //.... storeSortedMap(map,new FileWriter(new File("c:\\id.txt"))); Set<String,String> set; //.... storeSortedSet(set,new FileWriter(new File("c:\\trainval.txt")));
生成结果已经是排序的了
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