浅谈java中的TreeMap 排序与TreeSet 排序
TreeMap:
package com; import java.util.Comparator; import java.util.TreeMap; public class Test5 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub TreeMap<String, String> tree = new TreeMap<String, String>( new Comparator<Object>() { @Override public int compare(Object o1, Object o2) { // TODO Auto-generated method stub if(o1 == null || o2 == null){ return 0; } return o1.toString().compareTo(o2.toString()); } } ); tree.put("k", "1"); tree.put("ba", "2"); tree.put("z", "3"); tree.put("d", "4"); tree.put("e", "5"); tree.put("an", "6"); tree.put("c", "7"); for(String str : tree.keySet()){ System.out.println(str); } } }
经测试默认是按照 KEY 进行排序的。
但是可以写对象比较器,进行自定义排序。
TreeSet : 自定义倒序排序,默认按照正序排序,1,2,3,4,5,6
package com; import java.util.Comparator; import java.util.TreeSet; public class Test6 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub TreeSet<Object> tree = new TreeSet<Object>(new Comparator<Object>() { @Override public int compare(Object o1, Object o2) { // TODO Auto-generated method stub if(o1 == null || o2 == null){ return 0; } if(Integer.parseInt(o1.toString()) > Integer.parseInt(o2.toString())){ return -1; }else if(Integer.parseInt(o1.toString()) < Integer.parseInt(o2.toString())){ return 1; }else{ return 0; } } }); tree.add(4); tree.add(5); tree.add(6); tree.add(1); tree.add(2); tree.add(3); for(Object o : tree){ System.out.println(o); } } }
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