Golang 实现interface类型转string类型
看代码吧~
// Strval 获取变量的字符串值 // 浮点型 3.0将会转换成字符串3, "3" // 非数值或字符类型的变量将会被转换成JSON格式字符串 func Strval(value interface{}) string { var key string if value == nil { return key } switch value.(type) { case float64: ft := value.(float64) key = strconv.FormatFloat(ft, 'f', -1, 64) case float32: ft := value.(float32) key = strconv.FormatFloat(float64(ft), 'f', -1, 64) case int: it := value.(int) key = strconv.Itoa(it) case uint: it := value.(uint) key = strconv.Itoa(int(it)) case int8: it := value.(int8) key = strconv.Itoa(int(it)) case uint8: it := value.(uint8) key = strconv.Itoa(int(it)) case int16: it := value.(int16) key = strconv.Itoa(int(it)) case uint16: it := value.(uint16) key = strconv.Itoa(int(it)) case int32: it := value.(int32) key = strconv.Itoa(int(it)) case uint32: it := value.(uint32) key = strconv.Itoa(int(it)) case int64: it := value.(int64) key = strconv.FormatInt(it, 10) case uint64: it := value.(uint64) key = strconv.FormatUint(it, 10) case string: key = value.(string) case []byte: key = string(value.([]byte)) default: newValue, _ := json.Marshal(value) key = string(newValue) } return key }
补充:golang json 为map[string] interface{}
json字符串:
{"sn":1,"ls":false,"bg":0,"ed":0,"ws":[{"bg":0,"cw":[{"sc":0,"w":"还"}]},{"bg":0,"cw":[{"sc":0,"w":"有点"}]},{"bg":0,"cw":[{"sc":0,"w":"眼熟"}]}]}
需要将json格式中的w字段取出来,并且拼成结果串进行展示
1、从json数组中获取ws
2、ws是数组,数组元素为object
3、cw是数组,数组元素为object
4、w是string
5、从cw遍历获取w字段
解析代码:
func RecResultJsonToPlain() { var recResult string var dat map[string]interface{} json.Unmarshal([]byte(json_str), &dat) if v, ok := dat["ws"]; ok { ws := v.([]interface{}) for i, wsItem := range ws { wsMap := wsItem.(map[string]interface{}) if vCw, ok := wsMap["cw"]; ok { cw := vCw.([]interface{}) for i, cwItem := range cw { cwItemMap := cwItem.(map[string]interface{}) if w, ok := cwItemMap["w"]; ok { recResult = recResult + w.(string) } } } } } fmt.Println(recResult) }
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