springboot打成jar后获取classpath下文件失败的解决方案

springboot打成jar后获取classpath下文件

代码如下：

ClassPathResource resource = new ClassPathResource("app.keystore");
File file = resource.getFile();
FileUtils.readLines(file).forEach(System.out::println);

解决方式如下：

1. Spring framework

String data = "";
ClassPathResource cpr = new ClassPathResource("static/file.txt");
try {
    byte[] bdata = FileCopyUtils.copyToByteArray(cpr.getInputStream());
    data = new String(bdata, StandardCharsets.UTF_8);
} catch (IOException e) {
    LOG.warn("IOException", e);
}

2.use a file

ClassPathResource classPathResource = new ClassPathResource("static/something.txt");
InputStream inputStream = classPathResource.getInputStream();
File somethingFile = File.createTempFile("test", ".txt");
try {
    FileUtils.copyInputStreamToFile(inputStream, somethingFile);
} finally {
    IOUtils.closeQuietly(inputStream);
}

Resource resource = new ClassPathResource("data.sql");
BufferedReader reader = new BufferedReader(new InputStreamReader(resource.getInputStream()));
reader.lines().forEach(System.out::println);

String content = new ClassPathResourceReader("data.sql").getContent();

@Value("${resourceLoader.file.location}")
    @Setter
    private String location;
    private final ResourceLoader resourceLoader;
public void readallfilesfromresources() {
       Resource[] resources;

        try {
            resources = ResourcePatternUtils.getResourcePatternResolver(resourceLoader).getResources("classpath:" + location + "/*.json");
            for (int i = 0; i < resources.length; i++) {
                try {
                InputStream is = resources[i].getInputStream();
                byte[] encoded = IOUtils.toByteArray(is);
                String content = new String(encoded, Charset.forName("UTF-8"));
                }
            }
        } catch (IOException e) {
            throw new UncheckedIOException(e);
        }
}

springboot-项目获取resources下文件碰到的问题（classPath下找不到文件和文件名乱码）

项目是spring-boot + spring-cloud 并使用maven 管理依赖。在springboot+maven项目下怎么读取resources下的文件实现文件下载？

怎么获取resources目录下的文件？（相对路径）

方法一：

File sourceFile = ResourceUtils.getFile("classpath:templateFile/test.xlsx"); //这种方法在linux下无法工作

方法二：

Resource resource = new ClassPathResource("templateFile/test.xlsx"); File sourceFile = resource.getFile();

我使用的是第二种。

@PostMapping("/downloadTemplateFile")
    public JSONData downloadTemplateFile(HttpServletResponse response) {
        String filePath = "templateFile/test.xlsx";
        Resource resource = new ClassPathResource(filePath);//用来读取resources下的文件
        InputStream is = null;
        BufferedInputStream bis = null;
        OutputStream os = null;
        try {
            File file = resource.getFile();
            if (!file.exists()) {
                return new JSONData(false,"模板文件不存在");
            }
            is = new FileInputStream(file);
            os = response.getOutputStream();
            bis = new BufferedInputStream(is);
            //设置响应头信息
            response.setCharacterEncoding("UTF-8");
            this.response.setContentType("application/octet-stream; charset=UTF-8");
            StringBuffer contentDisposition = new StringBuffer("attachment; filename=\"");
            String fileName = new String(file.getName().getBytes(), "utf-8");
            contentDisposition.append(fileName).append("\"");
            this.response.setHeader("Content-disposition", contentDisposition.toString());
            //边读边写
            byte[] buffer = new byte[500];
            int i;
            while ((i = bis.read(buffer)) != -1) {
                os.write(buffer, 0, i);
            }
            os.flush();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
            return new JSONData(false,"模板文件不存在");
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                if(os != null) os.close();
                if(bis != null) bis.close();
                if(is != null) is.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return new JSONData("模板文件下载成功");
    }

高高兴兴的启动项目后发现还是找不到文件，错误日志：

java.io.FileNotFoundException: class path resource [templateFile/test.xlsx] cannot be resolved to URL because it does not exist
    at org.springframework.core.io.ClassPathResource.getURL(ClassPathResource.java:195)
    at org.springframework.core.io.AbstractFileResolvingResource.getFile(AbstractFileResolvingResource.java:129)
    at com.citycloud.parking.support.controller.operate.OperateBusinessUserController.downloadTemplateFile(OperateBusinessUserController.java:215)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:498)
    at org.springframework.web.method.support.InvocableHandlerMethod.doInvoke(InvocableHandlerMethod.java:209)
    at org.springframework.web.method.support.InvocableHandlerMethod.invokeForRequest(InvocableHandlerMethod.java:136)
    at org.springframework.web.servlet.mvc.method.annotation.ServletInvocableHandlerMethod.invokeAndHandle(ServletInvocableHandlerMethod.java:102)
    at org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter.invokeHandlerMethod(RequestMappingHandlerAdapter.java:877)
    at org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter.handleInternal(RequestMappingHandlerAdapter.java:783)
    at org.springframework.web.servlet.mvc.method.AbstractHandlerMethodAdapter.handle(AbstractHandlerMethodAdapter.java:87)
    at org.springframework.web.servlet.DispatcherServlet.doDispatch(DispatcherServlet.java:991)
    at org.springframework.web.servlet.DispatcherServlet.doService(DispatcherServlet.java:925)
    at org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:974)
    at org.springframework.web.servlet.FrameworkServlet.doPost(FrameworkServlet.java:877)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:661)
    at org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:851)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at org.springframework.boot.actuate.metrics.web.servlet.WebMvcMetricsFilter.filterAndRecordMetrics(WebMvcMetricsFilter.java:158)
    at org.springframework.boot.actuate.metrics.web.servlet.WebMvcMetricsFilter.filterAndRecordMetrics(WebMvcMetricsFilter.java:126)
    at org.springframework.boot.actuate.metrics.web.servlet.WebMvcMetricsFilter.doFilterInternal(WebMvcMetricsFilter.java:111)
    at org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:107)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)

因为我知道Resource resource = new ClassPathResource("templateFile/test.xlsx");就是到classPath*（注意这里有个*）下去找，然后就去项目本地的目录下找classPath下是否有这个文件（maven的classPath在 “target\classes”目录下），就发现并没有这个文件在。

后面仔细想想这是Maven项目啊，所以就找pom.xml文件去看看，突然想起：springboot的maven默认只会加载classPath同级目录下文件（配置那些），其他的需要配置<resources>标签：

<build>
  <resources>
      <resource>
        <directory>src/main/java</directory>
        <includes>
          <include>**/*.properties</include>
          <include>**/*.xml</include>
        </includes>
        <!--是否替换资源中的属性-->
        <filtering>false</filtering>
      </resource>
      <resource>
        <directory>src/main/resources</directory>
        <includes>
          <include>**/*.properties</include>
          <include>**/*.xml</include>
          <include>**/*.yml</include>
          <include>**/Dockerfile</include>
          <include>**/*.xlsx</include>
        </includes>
        <!--是否替换资源中的属性-->
        <filtering>false</filtering>
      </resource>
  </resources>
</build>

重新启动，再到classPath下看，发现有了这个文件了，同时也能获取了。如果文件名为中文的话就会出现乱码的情况。

怎么解决文件名中文乱码？

Access-Control-Allow-Origin →*
Access-Control-Allow-Credentials →true
Access-Control-Allow-Headers →accessToken,Access-Control-Allow-Origin,Content-Type,X-Requested-With,accept,Origin,Access-Control-Request-Method,Access-Control-Request-Headers
Access-Control-Allow-Methods →POST,GET,PUT,PATCH,DELETE,OPTIONS,HEAD
Access-Control-Max-Age →360
Content-disposition →attachment; filename="????????-??????????.xlsx"
Content-Type →application/octet-stream;charset=UTF-8
Transfer-Encoding →chunked
Date →Fri, 19 Apr 2019 06:47:34 GMT

上面是使用postman测试中文乱码response响应头相关信息。

后面怎么改都乱码，然后我就试着到浏览器中请求试试，结果发现只是postman的原因，只要文件名编码跟返回内容编码一致（"Content-disposition"和“ContentType”）就行：

this.response.setContentType("application/octet-stream; charset=iso-8859-1");
StringBuffer contentDisposition = new StringBuffer("attachment; filename=\"");
String fileName = file.getName();
contentDisposition.append(fileName).append("\"");
//设置文件名编码
String contentDispositionStr = new String(contentDisposition.toString().getBytes(), "iso-8859-1");
this.response.setHeader("Content-disposition", contentDispositionStr);

到此全部结束！

以上为个人经验，希望能给大家一个参考，也希望大家多多支持我们。