c#解析jobject的数据结构
首先下载newtonsoft.json
,增加引用using newtonsoft.json.linq
;
把jobject的内容提取出来,jobject的内容格式如下:
{ "code": 200, "msg": "success", "data": { "id": "12345678", "name": "张三", "sex": "男", "result": { "access_token": "49d58eacd7811e463429a1ae10b42173", "user_info": [ { "school": "社会大学", "major": "软件开发", "education": "本科", "score": 97 }, { "school": "湖南大学", "major": "软件工程", "education": "研究生", "score": 100 } ] } } }
代码如下:
1:新建类
public class userinfo { public string id { get; set; } public string name { get; set; } public string sex { get; set; } public string access_token { get; set; } public string school { get; set; } public string major { get; set; } public string education { get; set; } public string score { get; set; } }
2:获取值
jobject result = new jobject();//假设result为数据结构 userinfo userinfo = new userinfo(); userinfo.id = result["data"].value<string>("id");//id userinfo.name = result["data"].value<string>("name"); //name userinfo.sex = result["data"].value<string>("sex"); //sex userinfo.access_token= result["data"]["result"]["access_token"].tostring();//access_token jarray res = result["data"]["result"].value<jarray>("user_info"); jobject obj = jobject.parse(res[0].tostring());//只获取数据结构中第一个userinfo里的数据信息 userinfo.school = obj.value<string>("school"); //schoool userinfo.major = obj.value<string>("major");//major userinfo.education = obj.value<string>("education");//education userinfo.score= obj.value<string>("score");//score
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