剑指Offer之Java算法习题精讲数组与列表的查找及字符串转换
题目一
解法
class Solution {
public String toLowerCase(String s) {
StringBuilder sb = new StringBuilder();
for(int i = 0;i<s.length();i++){
char ch = s.charAt(i);
if('A'<=ch&&ch<='Z'){
ch = (char)(ch+32);
}
sb.append(ch);
}
return sb.toString();
}
}
题目二
解法
class Solution {
public int pivotIndex(int[] nums) {
int sum = 0;
for(int i = 0;i<nums.length;i++){
sum+=nums[i];
}
int left = 0;
int right = sum;
for(int i = 0;i<nums.length;i++){
right = right-nums[i];
if(i == 0){
left = 0;
if(right==left) return 0;
}else{
left+=nums[i-1];
if(right==left){
return i;
}
}
}
return -1;
}
}
题目三
解法
class Solution {
public List<Integer> selfDividingNumbers(int left, int right) {
ArrayList<Integer> list = new ArrayList<Integer>();
for(int i = left;i<=right;i++){
if(selfDividing) list.add(i);
}
return list;
}
public boolean selfDividing(int n) {
for (char c: String.valueOf(n).toCharArray()) {
if (c == '0' || (n % (c - '0') > 0))
return false;
}
return true;
}
}
题目四
解法
class Solution {
public char nextGreatestLetter(char[] letters, char target) {
int left = 0;
int right = letters.length;
while(left<right){
int mid = left+(right-left)/2;
if(letters[mid]<=target){
left = mid+1;
}else{
right = mid;
}
}
return left==letters.length?letters[0]:letters[left];
}
}
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